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3 years ago

The magnetic field around a long, straight wire is:

Physics

2 answers:

Margaret [11]3 years ago

7 0

Answer:

concentric with the wire

Explanation:

The magnetic field around a long straight wire carries an electric current form concentric circles around the wire

mezya [45]3 years ago

4 0

Answer:

1. concentric with the wire

Explanation:

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A wave that consists of changing electric and magnetic fields and that can travel through empty space is a(n) __________________

kap26 [50]

Electromagnetic wave

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3 years ago

Most savage races do not understand how the Galaxy works. Let's see how well you humans interpret a simple observation. The fact

Lesechka [4]

Answer:

Most wild races do not understand how the galaxy works. Let's see how well humans interpret a simple observation. The fact that we find O and B stars in the disk of our galaxy but not in the halo suggests that if there is knowledge about the galaxy, because it is known that there are stars, planets, black holes, halos, however there is still no the necessary technology, for the investigation and the refutation of the theories that currently exist on the theme of the galaxy.

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3 years ago

Two blocks can collide in a one-dimensional collision. The block on the left hass a mass of 0.40 kg and is initially moving to t

Dmitrij [34]

Answer:

The velocity of the first block is 1.15m/s while of the second block 2.56m/s.

Explanation:

Momentum is only conserved in an isolated system, and because this problem requires us to find the value of the two variables, we need two equations; therefore, to conserved momentum the energy must be released in to the system only after the collision has occurred.

Therefore, from conservation of momentum

$m_1v_1= m_1v_{1f}+m_2v_{2f}$

$0.4(2.4)= 0.4v_{1f}+0.5v_{2f}$

$\boxed{\:0.96= 0.4v_{1f}+0.5v_{2f}}$

and from conservation of energy

$\frac{1}{2}m_1v_1^2+1.2 = \frac{1}{2} m_1v_{1f}^2+\frac{1}{2}m_2v_{2f}^2$

$m_1v_1^2+2.4 = m_1v_{1f}^2+m_2v_{2f}^2}$

$\boxed{\:3.804= 0.4v_{1f}^2+0.5v_{2f}^2.}$

Thus, we have two equations and two unknowns

$(1). \: 0.4v_{1f}+0.5v_{2f}=0.96$

${(2). \: 0.4v_{1f}^2+0.5v_{2f}^2 =3.804$

which has solutions

$(v_{1f}, v_{2f}) = (1.15,2.56)$

and

$(v_{1f}, v_{2f}) = (1.15,-2.56)$

Since the blocks cannot pass through each other, the 0.5kg block cannot have $v_{2f} = -2.56m/s$ (moves to the left) while the 0.4 kg block has $v_{1f} = 1.15m/s$ (moves to the right); therefore, we take the first solution for the velocities:

$(v_{1f}, v_{2f}) = (1.15,2.56)$ .

Thus , the velocity of the first block is 1.15m/s while of the second block 2.56m/s.

5 0

3 years ago

Read 2 more answers

Part D

Montano1993 [528]

Answer:

Explanation:

I literally just did this question lol I hope I helped

4 0

3 years ago

Calculate the period (T) of uniform circular motion if the velocity is 40.0 m/s and centripetal acceleration is 20.0 m/s2.

kirill [66]

T is the time for a whole round.

centripetal acceleration = V^2/R,

20 = 40^2 / R, find R = 40^2/20 = 40*40/20 = 80 m, right?

Now, one round is L = 2*pi*R = 2*pi*80 = 160*pi

And T = L/v (distance/speed) = 160*pi/40 = 4*pi seconds, or ~ 12.57 s

3 0

3 years ago