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Dovator [93]
3 years ago
11

The water molecules now in your body were once part of a molecular cloud. Only about onemillionth of the mass of a molecular clo

ud is in the form of water molecules, and the mass density of such a cloud is roughly 4.0×10−21 g/cm3 Estimate the volume of a piece of molecular cloud that has the same amount of water as your body.
Physics
1 answer:
Rudik [331]3 years ago
5 0

To solve the problem we first need to define the nomenclature by which there is an X amount of water in our body. Let's call this a variable m, corresponding to the total mass in us and whose units are Kilograms.

Amount_{water} = m (Kg)

We understand that one millionth of this mass, a small fraction of it, is the equivalent of that of a Water Molecule.

Assuming this to have the same body of water in our body that amount should be approximately

m_{water}=10^6

Density of water molecule

\rho = 10^{-18}kg/m^3

V = \frac{m*10^6}{10^{-18}}

V = m*10^{24}m^3

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3 years ago
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3 years ago
What is the average speed in 4 seconds going 8 meters
gulaghasi [49]

Answer:

Explanation:

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6 0
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An object possessing an excess of 6.0x10^6 electrons has a net charge of
guajiro [1.7K]
A single electron has a charge of
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Therefore, if we have an excess of N=6.0\cdot10^6 electrons, the total net charge will be the product between the charge of a single electron and the total number of electrons in excess:
Q=Ne=(6.0\cdot10^6)(-1.6 \cdot 10^{-19}C)=9.6 \cdot 10^{-13}C
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