The object velocity is 282.4
Answer:
λ = 0.905m
Explanation:
TThe wavelength (λ) only depends on the harmonic (n) and the length of the string (L):
λ = 2L/n
λ = 2*1.81m /4
λ = 0.905m
If he runs at the same speed he will cover next 200m in 40s
that is at the average of 4.0m
Answer:
Option B. 2.8 s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 27 m/s
Angle of projection (θ) = 30
Acceleration due to gravity (g) = 9.8 m/s²
Time of flight (T) =?
The time of flight of the ball can be obtained as follow:
T = 2uSineθ / g
T = 2 × 27 × Sine 30 / 9.8
T = 2 × 27 × 0.5 / 9.8
T = 27 / 9.8
T = 2.8 s
Therefore, time of flight of the ball is 2.8 s
Answer: velocity = -0.65 speed =0.65
Explanation:
Velocity =speed+direction speed =distance/time
