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Andrews [41]
3 years ago
13

Answer Question QUICKILY please

Mathematics
1 answer:
Mariana [72]3 years ago
5 0
In a circle, the internal vertical angles have a formula of \frac{a + b}{2}

In this case, the formula would be: \frac{4x + 2x}{2} = \frac{6x}{2} = 3x

We know that whole circle is 12x. And 12x is equal to 360°. When we put that into equation: 12x = 360
x = 30

If x is 30°: 3x =3 \times 30 = 90

So, angle 7 is 90°.

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The answer would be negative 2
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Simplify.<br><br> 16 - 8 + 5x - 3x<br><br> 16 + 2x<br> 8 + 8x<br> 8 + 2x<br> 10x
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Answer:

8+2x

Step-by-step explanation:

Combine Like Terms:

<u>1</u><u>6</u><u>-</u><u>8</u>+5x-3x

8+<u>5</u><u>x</u><u>-</u><u>3</u><u>x</u>

8+2x

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In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s
Oksi-84 [34.3K]

Answer:

a) \mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

b) From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

c) P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

P(Z\geq2.070)=1-P(Z

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

\mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

Part c

For this case we want this probability:

P(\bar X \geq 285)

And we can use the z score defined as:

z=\frac{\bar x -\mu}{\sigma_{\bar x}}

And using this we got:

P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

And using a calculator, excel or the normal standard table we have that:

P(Z\geq2.070)=1-P(Z

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The equation that has a graph with a slope of -5/2 and passes through (6,-6)
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The answer is y=-5/2x+9 and the picture includes the equation and points. Hopefully, this helps.

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