I don't know about how to put that in standard form, but an equation has to have an equals sign... So, that would be an equation.
The first thing you should know are properties of exponents to solve the problem.
For this case the radical form is given by the writing of the expression in the form of root.
We have then:
t^-3/4 =4^root(t^-3)=4^root ((1)/(t^3))
answer t^-3/4=4^root((1)/(t^3))
Answer:
(8,-2)
Step-by-step explanation:
When reflecting something across the X axis the y axis coordinate is the one that will change to put the position further up or down. In this case we are moving it down to the same amount below the axis that it is now above it. That means that since it is currently 2 above the X axis it would then be 2 below the X axis making it at -2 so the coordinates would be (8,-2)
I hope this helps and please don't hesitate to ask if there is anything still unclear!
This answer uses NMF, which you can find out about on my profile:
Preliminary work:
Following the BIDMAS order of operations, we can calculate part of it already, and that's the 2•4, which equals 8.
Therefore, the equation now reads:
8+x = y
x = 5:
8+5 = 13
13 ≠ 16
13 ≠ y
x = 4:
8+4 = 12
12 = 12
12 = y
Therefore, the pair is (4, 12)
A) 2(1+2c)
2+4c = 2+4c
B) 6(14r-2t)
= 84r-12t
