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3 years ago

3/n of 32 is 24 solve for n

Mathematics

2 answers:

Sonbull [250]3 years ago

6 0

Answer:

n=4

Step-by-step explanation:

Of means multiplying so,

$\frac{3}{n}$ ×32=24

Multiply by n on both sides to get rid of the n denominator.

3×32=24n

Simplify the equation.

96=24n

Divide by 24.

n= 4

Ronch [10]3 years ago

5 0

N=4 3/n(32)=24 Divide both sides by 32 and simplify. 3/n=3/4

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Answer:

Well since he wrote the amount, he’s technically giving cash away so you basically jsut add everything.

98+456+29+381= 964

867-964= -97

His final balance would be -97

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3 years ago

A menu has three meat choices,

wolverine [178]

Answer:

18 ways

Step-by-step explanation:

Number of Meat choices = 3

Number of Vegetable choices = 3

Number of Desserts = 2

Number of ways dinner can be chosen :

Number of meat choices * Number of vegetable choices * number of desserts

3 * 3 * 2

= 18

Hence, dinner can be chosen in 18 different choices.

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2 years ago

Do Now 60: What are the formulas to find area for a square, triangle, rectangle, parallelogram, trapezoid, circle, ellipse and e

Alexandra [31]

Answer:

Area of a square = Length × Length

Area of a triangle = 1/2 base × height

Area of a rectangle = Length × breadth

Area of a parallelogram = base × height

Area of a trapezoid = 1/2 × sum of parallel sides × height

Area of circle = π × square of the radius

Area of ellipse = π × product of major and minor radii

Area of equilateral triangle = 1/2 base × height

Step-by-step explanation:

The area of a square is calculated by multiplying the length by itself.

The area of a triangle is calculated by multiplying half the base of the triangle by its height

The area of a rectangle is found by multiplying the length of the rectangle by its breadth

The area of a parallelogram is calculated by multiplying the base of the parallelogram by its height

The area of a trapezoid is found by multiplying half the sum of the two parallel sides by its height

The area of a circle is calculated by multiplying pi by the square of the radius of the circle

The area of an ellipse is found by multiplying pi by the product of the major and minor radii of the ellipse

The area of an equilateral triangle is calculated by multiplying half the base of the triangle by its height. The height is calculated using Pythagoras theorem

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3 years ago

Solve each equation below and write the answer on the line. Plan to spend 6 minutes total on this question. What is X?

zepelin [54]

A) x= -15/7
B) x= -2
C) x= -3
D) x= 3

6 0

3 years ago

Express the complex number in trigonometric form -6 + 6sqrt3i

marusya05 [52]

$\large\begin{array}{l}\\\\ \textsf{This is a complex number in }\mathsf{a+bi}\textsf{ form:}\\\\ \mathsf{z=-6+6\sqrt{3}\,i}\\\\ \textsf{where }\mathsf{a=-6~~and~~b=6\sqrt{3}.} \end{array}$

$\large\begin{array}{l}\\\\ \bullet~~\textsf{1}\mathsf{^{st}}\textsf{ step: Find the absolute value of z (complex modulus of z):}\\\\ \mathsf{|z|=\sqrt{a^2+b^2}}\\\\ \mathsf{|z|=\sqrt{(-6)^2+(6\sqrt{3})^2}}\\\\ \mathsf{|z|=\sqrt{36+36\cdot 3}}\\\\ \mathsf{|z|=\sqrt{36\cdot 108}}\\\\ \mathsf{|z|=\sqrt{144}}\\\\ \mathsf{|z|=12} \end{array}$

$\large\begin{array}{l}\bullet~~\textsf{2}\mathsf{^{nd}}\textsf{ step: Find the argument }\mathsf{\theta}\textsf{ of z:}\\\\ \mathsf{arg(z)=\theta}\\\\ \textsf{is an angle that satisfies the following conditions:}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{a}{|z|}=\dfrac{a}{\sqrt{a^2+b^2}}}\\\\ \mathsf{sin\,\theta=\dfrac{b}{|z|}=\dfrac{b}{\sqrt{a^2+b^2}}} \end{cases}\qquad\quad-\pi$

$\large\begin{array}{l}\textsf{For }\mathsf{z=-6+6\sqrt{3}\,i,}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{-6}{12}=-\,\dfrac{1}{2}}\\\\ \mathsf{sin\,\theta=\dfrac{6\sqrt{3}}{12}=\dfrac{\sqrt{3}}{2}} \end{cases}\\\\\\ \textsf{Since}\\\\ \mathsf{cos\,\theta0,}\\\\ \theta\textsf{ lies in the 2}\mathsf{^{nd}}\textsf{ quadrant.}\\\\\\\textsf{Therefore,}\\\\ \mathsf{\theta=\dfrac{2\pi}{3}~rad~~(120^\circ)} \end{array}$

$\large\begin{array}{l}\bullet~~\textsf{3}\mathsf{^{rd}}\textsf{ step: Express z in the trigonometric form:}\\\\ \begin{array}{rcl} \mathsf{z}&\!\!=\!\!&\mathsf{|z|\cdot (cos\,\theta+i\,sin\,\theta)}\\\\ \mathsf{-6+6\sqrt{3}\,i}&\!\!=\!\!&\mathsf{12\cdot \left(cos\, \dfrac{2\pi}{3}+i\,sin\,\dfrac{2\pi}{3}\right)\qquad\quad\checkmark} \end{array} \end{array}$

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$\large\textsf{I hope it helps.}$

Tags: <em>complex number trigonometric form trig absolute value modulus argument angle</em>

4 0

3 years ago