The sum of the measures of the angles of a triangle is 180 deg.
m<J + m<K + m<L = 180
72 + 36 + m<L = 180
m<L = 72
Both angles J and L measure 72 deg.
Angles J and L are base angles measuring 72 deg.
Angle K is the vertex angle measuring 36 deg.
Answer:
Perimeter and area of drawing
Perimeter= 10 In
Area = 6.25 In²
Perimeter and area of object
Perimeter = 51.836 mm
Area = 167.936 mm²
Step-by-step explanation:
We are dealing with a square object, so let's talk about the drawing first.
The length of one side = 2.5 In
Perimeter of square= 4L
Perimeter = 4*2.5
Perimeter= 10 In
Area = L*L
Area = 2.5*2.5
Area = 6.25 In²
Letd note that 1 inch =
25.4 millimetres
So 2.5 Inch = 2.5 * 25.4
2.5 In = 63.5 mm.
25.4 mm is to 5mm
63.5 mm is to (63.5*5)/24.5
63.5mm is to 12.959 mm
So the length of actual object is 12.959mm
The perimeter = 4*12.959
Perimeter = 51.836 mm
Area = 12.959²
Area = 167.936 mm²
Answer:
![2\sqrt10](https://tex.z-dn.net/?f=2%5Csqrt10)
6.3 to the nearest 10th
Step-by-step explanation:
Hope this helped :)
a= -5 , -2
b= 1 , 0
not sure if that helped sorry if i didnt