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3 years ago

Which of the following polynomials is in standard form?

Mathematics

2 answers:

ASHA 777 [7]3 years ago

6 0

Answer:

z5+z15-z3-4

hope it's correct

bogdanovich [222]3 years ago

3 0

Z25-z16+z14-4z is in standard form.

If the numbers after the variable are powers this is correct. In the future write it like this so people could help you easier (6z^2 instead of 6z2)

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Gas and oil costs = $1,100.00 Repair/Maintenance = $800.00 Operating cost per mile = $0.14 Miles driven =

Greeley [361]

Hi there

Miles driven=
(1,100+800)÷0.14
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2 years ago

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What type of symmetry does this figure have?

BARSIC [14]

Rotational symmetry. Because you can rotate it and put a line through it and it would all look the same

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2 years ago

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Identify the property used in each step of solving the inequality 3x – 2 > -4.

jasenka [17]

Answer:

2) is addition property

3) is multiplication property

Step-by-step explanation:

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2 years ago

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Prove that sin3a-cos3a/sina+cosa=2sin2a-1

Sloan [31]

Answer:

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

Step-by-step explanation:

we are given

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

we can simplify left side and make it equal to right side

we can use trig identity

$sin(3a)=3sin(a)-4sin^3(a)$

$cos(3a)=4cos^3(a)-3cos(a)$

now, we can plug values

$\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}$

now, we can simplify

$\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}$

$\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}$

$\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}$

now, we can factor it

$\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}$

$\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can use trig identity

$sin^2(a)+cos^2(a)=1$

$\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can cancel terms

$=3-4(1-sin(a)cos(a))$

now, we can simplify it further

$=3-4+4sin(a)cos(a))$

$=-1+4sin(a)cos(a))$

$=4sin(a)cos(a)-1$

$=2\times 2sin(a)cos(a)-1$

now, we can use trig identity

$2sin(a)cos(a)=sin(2a)$

we can replace it

$=2sin(2a)-1$

so,

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

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3 years ago

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Summarize what happens when the number of spins in experimental probability gets closer to 100.

IrinaVladis [17]

Answer:

B: The outcomes get closer to the theoretical probability for the same experiment.

Step-by-step explanation:

I hope this helps :)

Plz mark brainliest ♥

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3 years ago