Answer:
Magnetic field, 
Explanation:
It is given that,
Velocity of proton, 
Magnetic force, 
Charge of proton, 
We need to find the strength of the magnetic field if there is a 45° angle between it and the proton's velocity. The formula for magnetic force is given by :



B = 0.0000416 T

Hence, this is the required solution.
Answer:
How is the rational inertia defined.
Answer. A
The acceleration of the box is 
Explanation:
The acceleration of the crate can be found by analyzing the forces acting along the direction parallel to the incline. We have three forces:
- The force of push, F = 125 N, pushing up along the incline
- The force of friction,
, acting down along the incline - The component of the weight parallel to the incline,
, also acting downward
Taking into account the direction of each force, the equation of motion along this direction is:

where
F = 125 N

is the weight of the crate
is the angle of the incline
is the mass of the box
a is the acceleration
And solving for a, we find:

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Answer: 2.67 m/s
Explanation:
Given
Mass of block A is 
mass of block B is 
The initial velocity of block A 
the initial velocity of block B is 
After collision velocity of block A is 
Conserving momentum

The momentum of block A after the collision is 
Therefore, there is no change in sign.
Answer:
Approximately
, assuming that air resistance is negligible and that
.
Explanation:
The ball starts to fall the moment it rolls of the edge of the table.
- Let
denote the initially height of this ball. - Let
denote the initial vertical velocity of this ball.
Assume that gravity is the only force acting on the ball during its fall (that is, there's no air resistance to slow the ball down.) The vertical acceleration of this ball during the fall would be constantly equal to
(negative because the ball is accelerating downwards.)
The following SUVAT equation would give the height
of this ball at time
:
.
Since the table is horizontal, the vertical velocity of this ball would be
the moment it rolls of the edge. In other words:
.
The initial height of this ball when it rolls of the table is
, same as the height of the table.
Hence, the height
of this ball at time
would be:
.
At
, the height of this ball would be
. The ball would be on the ground by the time
, Set the right-hand side of this equation to
and solve for the time
at which the ball is on the ground:
.
.
.
Substitute in the values
and
:
.
In other words, the ball would be in the air for approximately
. (The initial horizontal velocity of this ball does not affect the duration of this fall.)