Ask question

Ask question

All categories

3 years ago

11

A car is initially traveling at 12 m/s when the driver sees a yellow light ahead. He accelerates at a constant 7 m/s^2 for 6 s i

n order to make it through the intersection. What was the velocity at the end of this time?

1 answer:

Vitek1552 [10]3 years ago

3 0

Answer:

v = 54m/s

Explanation:

$a = \frac{v - u}{t}$

a = 7m/s²

u = 12m/s

t = 6s

7 = (v-12)/6

v - 12 = 42

v = 54m/s

(Correct me if i am wrong)

You might be interested in

If the charges attracting each other in the preceding problem have equal magnitudes,show that the magnitude of each charge is 2.

Schach [20]

Answer:

The magnitude of each charge is $2.82\times10^{-6}\ C$

Explanation:

Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.

We need to calculate the magnitude of each charge

Using formula of force

$F=\dfrac{kq^2}{r^2}$

Where, q = charge

r = separation

Put the value into the formula

$20=\dfrac{9\times10^{9}\times q^2}{(6\times10^{-2})^2}$

$q^2=\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}$

$q=\sqrt{\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}}$

$q=2.82\times10^{-6}\ C$

Hence, The magnitude of each charge is $2.82\times10^{-6}\ C$

6 0

3 years ago

A vertical spring launcher is attached to the top of a block and a ball is placed in the launcher, as shown in the figure. While

kvasek [131]

For a vertical spring launcher is attached to the top of a block and a ball is placed in the launcher, the position of the ball will be behind the box

<h3>What will be the position of the ball relative to the spring launcher?</h3>

Generally, the equation for the conservation of momentum principle is mathematically given as

(M+m) V1 = M*V2

Therefore, with the ball moving forward we have that; the ball at top it wii be behind the box,

Read more about Motion

brainly.com/question/605631

7 0

2 years ago

two bumper cars collide into each other and each caor jolts backwards what law is this isnt it newtons second law?

Yanka [14]

Yes because the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

5 0

3 years ago

u are holding the axle of a bicycle wheel with radius30 cm and mass 1.05 kg. You get the wheel spinning at arate of 77 rpm and t

DedPeter [7]

Answer:

-5.9 rad/s^{2}

Explanation:

radius (r) = 30 cm = 0.3 m

mass (m) = 1.05 kg

initial speed (u) = 77 rpm

final speed (v) = 0 rpm

time (t) = 1.37 s

angular acceleration = $\frac{(final speed-initial speed)rad/s}{time}$

therefore

initial speed (U) = 77 rpm = 77 x (2π/60) = 8.06 rad/s

final speed (v) = 0 rpm = 0 rad/s

angular acceleration = $\frac{0-8.06}{1.37}$ = -5.9 rad/s^{2}

5 0

3 years ago

Read 2 more answers

In which beaker were the particles moving the most slowly?

viva [34]

Answer:

It might be wrong but d? i think

4 0

3 years ago