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docker41 [41]
3 years ago
15

Name the forces acting on a plastic bucket container water held above ground level in your hand. Discuss why the forces acting o

n the bucket do not bring a change in its state of motion. (Please briefly describe your answers only)
Physics
1 answer:
SashulF [63]3 years ago
5 0

There are two forces at play:

  • The gravitational force acting downward due to the mass of the bucket and the water that it contains.
  • The upward force that your hand exerts on the bucket.

If the magnitude of the force your hand exerts on the bucket equals the magnitude of the gravitational force, the bucket is in static equilibrium. That means the bucket is not moving and the forces acting on it balance each other out, making the net force 0.

Having 0 net force means the bucket doesn't undergo any acceleration, or change in motion.

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A car driver takes a total of two hours to make a journey of 75 km. She has a coffee
Vlada [557]

Answer:

34 km

Explanation:

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3 years ago
What is speed of third cosmic velocity?
slava [35]
It's about 42 km/s! (kilometers per second) Hope I helped! :)
4 0
3 years ago
A piston in an internal combustion engine applies torque during 150° of each full rotation of the crankshaft to which it is conn
aalyn [17]

Answer:

T=1.566 N.m

Explanation:

Given that:

rotational speed of the scrank shaft, N = 2500 rpm

power produced by one cylinder, P = 410 W

We know, in case of rotational power:

P=\frac{2\pi.N.T}{60}

where: T= torque

Substituting the respective values in the above eq.

410=\frac{2\pi\times2500\times T}{60}

T= \frac{410\times60}{2\pi\times2500}

T=1.566 N.m is the torque applied by the each piston of the engine.

4 0
3 years ago
Why does the book with more mass feel heavier in your hand
jok3333 [9.3K]

Answer:

because the book's is covered by papers

6 0
2 years ago
If you went to a planet that had the twice the radius as Earth, but the same mass, a 1 kg pineapple would have a weight of
kicyunya [14]

Use the law of universal gravitation, which says the force of gravitation between two bodies of mass <em>m</em>₁ and <em>m</em>₂ a distance <em>r</em> apart is

<em>F</em> = <em>G m</em>₁ <em>m</em>₂ / <em>r</em>²

where <em>G</em> = 6.67 x 10⁻¹¹ N m²/kg².

The Earth has a radius of about 6371 km = 6.371 x 10⁶ m (large enough for a pineapple on the surface of the earth to have an effective distance from the center of the Earth to be equal to this radius), and a mass of about 5.97 x 10²⁴ kg, so the force of gravitation between the pineapple and the Earth is

<em>F</em> = (6.67 x 10⁻¹¹ N m²/kg²) (1 kg) (5.97 x 10²⁴ kg) / (6.371 x 10⁶ m)²

<em>F</em> ≈ 9.81 N

Notice that this is roughly equal to the weight of the pineapple on Earth, (1 kg)<em>g</em>, where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity, so that [force of gravity] = [weight] on any given planet.

This means that on this new planet with twice the radius of Earth, the pineapple would have a weight of

<em>F</em> = <em>G m</em>₁ <em>m</em>₂ / (2<em>r</em>)² = 1/4 <em>G m</em>₁ <em>m</em>₂ / <em>r</em>²

i.e. 1/4 of the weight on Earth, which would be about 2.45 N.

7 0
3 years ago
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