I believe the answer is Natural Laws
by angular momentum conservation we will have
angular momentum of child + angular momentum of merry go round = 0
angular momentum of child = mvR
m = mass of child
R = radius of child
v = speed = 2 m/s
now let's say moment of inertia of merry go round is I
so we will have
so merry go round will turn in opposite direction with above speed
Linear momentum has to be conserved. It was zero before the thread eas burned ... when nothing was moving ... so the momentum of the masses moving in opposite directions has to add up to zero. ... Momentum = mass times speed. ... In one direction, you have 5 kg times 1/5 m/s= 1 kg-m/s. ... We need 1 kg-m/s in the other direction. ... 7 kg times speed = 1 kg-m/s. ... Can you finish it from here ?
The maximum torque she can apply to the spark plug is 12.76 Nm.
<h3>
What is torque?</h3>
Torque is the rotational equivalent of linear force obtained by taking the product of force and the radius of the applied force.
τ = Fr
where;
- F is the applied force
- r is the radius
The maximum torque she can apply to the spark plug is calculated as follows;
τ = 58 x (0.22)
τ = 12.76 Nm
Thus, the maximum torque she can apply to the spark plug is 12.76 Nm.
Learn more about torque here: brainly.com/question/14839816
