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LekaFEV [45]
3 years ago
12

Peter rides his bike 5 blocks north and then 10 blocks east. What is his displacement? What is his total distance traveled?

Physics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

5 blocks east. His total distance is 15 feet.

Explanation:

I hope that this helps! Have a good day!

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The table represents the speed of a car in a northern direction over several seconds. A 2-column table with 5 rows. The first co
Oksanka [162]

Answer:

Column 1 should be titled “Time,” and Column 2 should be titled

“Velocity.” ⇒ 1st answer

Explanation:

* <em>Lets revise some definitions of graphs</em>

A velocity-time graph represents the speed and direction an object

travels over a period of time.

Velocity-time graph is called speed-time graph.

The vertical axis of a velocity-time graph represents the velocity of the

object and horizontal axis represents the time from the initial position

In an acceleration time graph y-axis represents the acceleration, and

x-axis represents the time

The table represents the <em>speed of a car in a northern</em> direction over

several seconds

That means the data in the table represent the <em>velocity</em> of the car in a

certain time

Time (s)             Velocity (m/s)  

   0                            5

   2                            10

   4                            15

   6                            20

   8                            25

   10                           30

Column 1 would be on the x-axis

x-axis represents the time

Column 2 would be on the y-axis

y-axis represents the velocity

Column 1 should be titled “Time,” and Column 2 should be titled

“Velocity.”

3 0
3 years ago
Read 2 more answers
The white ring seen here, within our solar system, is a(n) ________ belt.
Gelneren [198K]
Asteroid belt :-) hope it helped
3 0
3 years ago
Read 2 more answers
Circular Motion A 650-kg car moving at 8.5 m/s takes a turn around a circle with a radius of 48.0 m. Determine the acceleration
ollegr [7]

Answer:

Explanation:

The mass of the car doesn't matter because On a flat curve the mass of the car does not affect the speed at which it can stay on the curve. You would need the mass if you were solving the the centripetal force acting on the car, but not the acceleration.

a=\frac{v^2}{r} and filling in

a=\frac{(8.5)^2}{48.0} and we need 2 significant digits in our answer. That means that

a = 1.5 m/sec²

8 0
3 years ago
Read the information and study the image.
erastova [34]

Answer:

It is impossible to detect underground water from the surface. Dowsing practitioners refuse to explain their secrets.

Explanation:

4 0
3 years ago
A rope of length L has circular cross-sectional area A and density rho = m/V , where m is the mass of the rope and V = A · L is
hram777 [196]

Answer: µ = ρ¹ * A¹

Where x=1 and y=1

Explanation: According to the question, the mass per unit length (µ) is related to the density (ρ) and area A are related by the formulae below

µ = ρ * A

The dimension for each of these quantities is given below

Since µ is mass per unit length, unit is Kg/m and the dimension is ML^-1

ρ is density with unit kg/m³ and the dimension is ML^3

A is area with unit m², thus the dimension is M^2

Note that using dimensional analysis means we will be using the 3 fundamental quantities (mass, length and time) in our analysis.

Their dimensions below

Mass = M

Length = L

Time = T

Since the mass per unit length is related to density and area, we have a mathematical equation to provide a solution as shown below

µ = ρ^x * A^y.

By getting the power of x and y we will be able to get the formula that relates the quantities.

This is done by slotting in the dimensions of the respective quantities.

ML^-1 = (ML^-3)^x * (L²) ^y

By using law of indices on the right hand side of the equation, we have that

ML^-1 = (M^x * L^-3x) * (L^2y)

Also applying law of indices on the right hand side, we have that

ML^-1 = (M^x) * (L^-3x +2y)

The next step is to relate equal variables on both sides

For the M variable

M¹ = M^x which results to

x = 1

For the L variable

L^-1 = L^-3x+2y which results to

-1 = - 3x +2y

But x = 1

We have that

-1 = - 3(1) +2y

-1 = - 3 + 2y

-1 +3= 2y

2 = 2y

y = 1

Thus x=1 and y=1 and the formulae that relates the quantities is

µ = ρ¹ * A¹

3 0
3 years ago
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