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Katyanochek1 [597]
3 years ago
14

10Ω resistor and a 5 Ω are connected in parallel. This pair is then connected in series in with another 4 Ω resistor. What is th

e equivalent resistance of the circuit?
Physics
1 answer:
Dmitrij [34]3 years ago
5 0

Answer:

7.33 Ω

Explanation:

10Ω resistor and a 5 Ω are connected in parallel

so,

R₁=(10X5)/(10+5)

   =(50/15) Ω

   =3.33 Ω

This pair is then connected in series in with another 4 Ω resistor

R₂=R₁+4

    =(3.33+4) Ω

    =7.33 Ω

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F_{R}=ma \\ W+E-N=ma \\ N =W+E \\ N=5*10^2+10*10^2 \\ \boxed {N=1.5*10^3N}

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Answer:

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A force of 5N produces an acceleration of 8m/s2 on mass m1, and an acceleration of 24m/s2 on a mass m2. What acceleration would
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The acceleration that the same force will provide if both masses are tied together is; 6.0 m/s².

<h3>How to find the Acceleration?</h3>

We are given;

Force; F = 5 N

Acceleration of the first mass, a₁ = 8.0 m/s²

Acceleration of the second mass, a₂ = 24 m/s²

Formula for force is;

F = ma

Let us find both masses; m₁ and m₂.

m₁ = F/a₁

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Read more about Acceleration at; brainly.com/question/605631

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