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3 years ago

Multiply or divide as indicated. 5a2.6a4

Mathematics

2 answers:

Elodia [21]3 years ago

8 0

Answer:

$30 {a}^{6}$

Step-by-step explanation:

Hope it is helpful...

Vesna [10]3 years ago

3 0

Answer:

3a^6

Step-by-step explanation:

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Solve for x: |x − 2| + 10 = 12 (1 point)

True [87]

Answer:

I think that would be 1

Step-by-step explanation:

Do everything in the lines before anything else. -2 becomes a 2 and then you add that with the 12 and divide 12 on both sides to get one.

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2 years ago

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At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

7 0

3 years ago

Find the area. simply your answer <br><br> 2x<br> 3x

Firdavs [7]

The area of a triangle is always:

A=bh/2 (base times the height divided by 2)

A=3x(2x)/2

A=6x^2/2

A=3x^2

...

7 0

3 years ago

Read 2 more answers

Find how X and y compare when log X = 6.6 and log y = 3.6

asambeis [7]

Answer

x = 3981071.7055

y = 3981.0717

x > y

Step by step explanation

First let's find the value of x and y by taking anti - log.

log X = 6.6

X = log^ -1 (6.6)

X = 3981071.7055

Similarly,

log Y = 3.6

Y = log ^(-1) 3.6

Y = 3981.0717

Once we found the values of X and Y , we can easily compare them.

Here x > y

Hope you will understand the concept.

Thank you. :)

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3 years ago

Alfred has a 30 dollar gift voucher.He plans to buy as many video games as he can.The cost of each game is 10 dollars.There is a

kotykmax [81]

10+2=12 30 divided by 12 = 2.5

5 0

3 years ago