Answer:
Step-by-step explanation:
Answer:
yes it can
.........................................
Answer:
Not correct
Step-by-step explanation:
Sample 8 has one free throw, sample 9 has 3 free throw success,
sample 10 has 3 free throw success
sample 11 has 5 free throw success
sample 12 has 5 free throw success
sample 13 has 2 free throw success
sample 14 has 1 free throw success;
See one sample should contain 15 free throw and the probability of success should be 0.7
Let's look at sample 8
Total no of success is 1
Total no of free throws 15
Probability is 1/15 = 1/15 * 100 =6.67%
Similarly you can do so for the others.
2(1/2)-1(4/7)
(5/2)-(11/7) multiply the big 2 with the two on the bottom and add it with one and put it on top
same thing but with the whole number with the seven and adding it with whatever is on top
(35/14)-(22/14)
multiply (5/2) with (7/7) to have the same denominator and (11/7) with (2/2)
(13/14)
