X = 3/2 or 1 1/2
Both of the equations equal -10, therefor the equations are equal.
Answer:
128 deg
Step-by-step explanation:
The sum of the measures of the angles of a polygon of n sides is
(n - 2)180
A trapezium has 4 sides, so the sum of the measures of the angles is
(4 - 2)180 = 2(180) = 360
<em>m<CBE + m<C + m<D + m<DEB = 360</em>
Angles ABC and CBE are a linear pair so the sum of their measures is 180 deg.
m<ABC + m<CBE = 180
115 + m<CBE = 180
m<CBE = 65
m<C = x
m<D = 90
Angles DEB and DEF are a linear pair so the sum of their measures is 180 deg.
m<DEB + m<DEF = 180
m<DEB + m<103 = 180
m<DEB = 77
<em>m<CBE + m<C + m<D + m<DEB = 360</em>
65 + x + 90 + 77 = 360
x + 232 = 360
x = 128
Answer: 128 deg
<em />
Answer:
-18+9k
Step-by-step explanation:
If you use the distributive property, you get:
(-3*6) and (-3*-3k)
If you simplify each of them you get:
-18+9k
Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
A = P(1 + r)^t is the interest formula
A = 1000(1 + .02)^t
A = 1000(1.02)^t
I'm not sure which of your two answers A or C have the t raised to a power but you need to choose the one with the t raised to a power.
