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spayn [35]
3 years ago
9

A car is heading north on I-10 at 75 mph for 315 miles how long did it take the car to drive this distance

Chemistry
1 answer:
Nina [5.8K]3 years ago
6 0

4.2 hours, do 315 miles / 75 miles per hour

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And non-flammable gases<br> Noble gases are<br> that have low chemical
gtnhenbr [62]

Answer:

  • Noble gases are <u>odorless, colorless,</u> and nonflammable gases that have low chemical <u>reactivity</u><u>.</u>
  • The full <u>valence electron shells</u><u> </u>of these atoms make noble gases extremely <u>stable</u><u>.</u>
  • & they are <u>unlikely to form chemical bonds</u><u> </u>because they have little tendency to gain or lose

<u>electrons.</u>

5 0
3 years ago
If two gases a and b in separate 1 liter containers
Anton [14]

The pressure exerted when both gases are put together in a single 1 liter container is 5 atm.

<h3>What is pressure?</h3>

Pressure is the force exerted by any object on another object.

Given that, a and b separate 1 liter containers and exert pressure of 2 atm and 3 atm respectively.

When both gases a and b exert together, the pressure then

2 atm + 3 atm = 5 atm.

Thus, the pressure exerted when both gases are put together in a single 1 liter container is 5 atm.

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7 0
2 years ago
All energy originates from the _______.
Phantasy [73]

Answer:

sun

Explanation:

because all plants use energy from the sun to make food and grow

7 0
3 years ago
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If the distance between two objects is decreased to - of the original
Charra [1.4K]

Answer:

The new force will be \frac{1}{100} of the original force.

Explanation:

In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.

That said, let's say that our equation for the initial force is:

F = G\frac{m_1m_2}{R^2}The problem states  that  the distance decrease to 1/10 of the original distance, this means:[tex]R_2 = \frac{1}{10}R

And the force at this distance would be written in terms of the same equation:

F_2 = G\frac{m_1m_2}{R_2^2}

Find the ratio between the final and the initial force:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{R_2^2}}{G\frac{m_1m_2}{R^2}}

Substitute the value for the final distance in terms of the initial distance:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{(\frac{R}{10})^2}}{G\frac{m_1m_2}{R^2}}

Simplify:

\frac{F_2}{F} = \frac{\frac{1}{100R^2}}{\frac{1}{R^2}}=\frac{1}{100}

This means the new force will be \frac{1}{100} of the original force.

8 0
3 years ago
Besides water, which of the following compounds are found most in sea water?
Tju [1.3M]
The answer is sodium chloride.

Explanation:

Sodium chloride refers to table salt, and is the most abundant of salts found in seawater.
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2 years ago
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