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Darina [25.2K]
3 years ago
5

Sodium hydroxide + nitrate acid

Chemistry
1 answer:
labwork [276]3 years ago
5 0
The correct anwser would be nitric acid!!!
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Longshore drift occurs when: the repetitive action of swash and backwash transports sediment sideways along the coas powerful wa
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<span>Longshore drift is a geographical process that consists of the transportation of sediments (clay, silt, sand and shingle) along a coast at an angle to the shoreline, which is dependent on prevailing wind direction, swash and backwash. This process occurs in the littoral zone, and in or close to the surf zone.</span>
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3 years ago
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Which has greater heat capacity—iron, tin, or bismuth? Why do you say this?
emmasim [6.3K]

Answer:

Bismuth, because when three cubes of the same mass were heated and dropped into the same temperature water, the water the bismuth cube was dropped in heated up much less than the water with iron or tin.

REWRITE THIS IN YOUR OWN WORDS PLEASE, THANK YOU.

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4 0
3 years ago
Which group has the greatest number of valence electrons?
mylen [45]

Answer:

Noble gases

Explanation:

No need

7 0
3 years ago
You have 627 ml of 5.04 M HCl. Using a volumetric pipet, you take 229 ml of that solution and dilute it to 921 ml in a volumetri
trasher [3.6K]

Answer:

0.653

Explanation:

1)

M1V1 = M2V2

M1 = 5.04 M

V1 = 229 mL ( you take only this volume)

V2 = 921 mL

5.04*229 = M2 * 921

M2 = (5.04*229)/921 Molarity

2)

M1V1 = M2V2

M1 = (5.04*229)/921

V1 = 100 mL

V2= 192 mL

(5.04*229)/921 *100 = M2 * 192

M2 = [(5.04*229)/921 *100]/192 = 0.653 final molarity

8 0
3 years ago
PLEASE HELP- I WILL GIVE BRAINLIEST AND THANKS
julsineya [31]

Answer:

The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams

Explanation:

The question is with regards to density calculations

The density of the given sodium carbonate solution, ρ = 0.4 g/dm³

The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³

Density \ of \ an \ object, \rho  = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }

\rho = \dfrac{m}{V}

Therefore, we have;

The \ Density \ of \ the \ sodium \ carbonate, \ \rho  = 0.4 \ g/dm^3 =  \dfrac{m }{ 0.01 \ dm^3 }

The mass, "m", of the sodium carbonate in  = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g

The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.

8 0
3 years ago
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