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irina1246 [14]
3 years ago
8

Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a^2 – 18 square units. Which i

s an equivalent expression for the area of the hexagon based on the area of a triangle? A. 6(4a^2 – 3) B. 6(8a^2 – 9) C. 6a(12a – 9) D. 6a(18a – 12)
Mathematics
2 answers:
netineya [11]3 years ago
6 0

we know that

The area of the hexagon is equal to the sum of the areas of the six equilateral triangles

Let

x-------> area of one equilateral triangle

so

6x=24a^{2} -18

Divide by 6 both sides

x=4a^{2} -3 -------> area of one equilateral triangle

To find an equivalent expression for the area of the hexagon based on the area of a triangle, multiply the area of one equilateral triangle by 6

6*(4a^{2} -3)

therefore

the answer is

The equivalent expression is equal to 6*(4a^{2} -3)

Leviafan [203]3 years ago
3 0

6(4a2 – 3) is an equivalent expression for the area of the hexagon based on the area of a triangle.

 

<span>A regular </span>hexagon<span> <span>can be cut into six equilateral triangles, and an equilateral triangle can be divided into two 30°- 60°- 90° triangles. So if you're doing a </span></span>hexagon<span> problem, you may want to cut up the figure and use equilateral triangles or 30°- 60°- 90° triangles to help you find the apothem, perimeter, or </span>area.

 

The correct answer between all the choices given is the first choice or letter A. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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7 0
3 years ago
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

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For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

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3 years ago
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Natasha2012 [34]
Add 35+ 72.5=107.5 that should give you your answer for c and the answer for d is acute because the triangle would have to be 360 to be Obtused and it's not a right triangle because you don't have a 90 degree angle
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3 years ago
The number 16 has four fourth roots. In other words, there are four complex numbers that can be entered in the square in the equ
Tems11 [23]

Answer:

Step-by-step explanation:

Hello, we know that the z complex solutions of

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Effectus [21]
4260 is the answer

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