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2 years ago

James asked 60 pupils which drink they liked best from cola, milk and water.

Mathematics

1 answer:

Olin [163]2 years ago

6 0

Answer:

Step-by-step explanation:

There are 60 pupils in the survey

32 are boys, so we assume 28 are girls

12 of the boys said cola was their favourite

4 boys liked water best.

That is a total of 16 boys who prefer either cola or water out of 32 total boys

There are 16 boys leftover who must have milk as there favourite

9 girls liked water best

21 pupils altogether said milk was there favourite. We know there are 16 boys who said milk was there favourite, meaning 5 of these pupils must be girls.

That means 9 girls have water as their favourite and 5 have milk as their favourite, a total of 14

We know there are 28 girls total. That means 14 of them must have listed cola as their favourite drink.

There are 14 girls and 12 boys who said cola was their favourite, a total of 26 pupils

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In a study of academic procrastination, the authors of a paper reported that for a sample of 471 undergraduate students at a mid

AnnZ [28]

Answer:

95% confidence interval for the mean time spent studying for the final exam for students taking introductory psychology at this university is [6.85 hours, 7.43 hours].

Step-by-step explanation:

We are given that a sample of 471 undergraduate students at a midsize public university preparing for a final exam in an introductory psychology course, the mean time spent studying for the exam was 7.14 hours and the standard deviation of study times was 3.20 hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time spent studying for the exam = 7.14 hours

$\sigma$ = population standard deviation = 3.20 minutes

n = sample of undergraduate students = 471

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $7.14-1.96 \times {\frac{3.20}{\sqrt{471} } }$ , $7.14+1.96 \times {\frac{3.20}{\sqrt{471} } }$ ]

= [6.85 hours , 7.43 hours]

Therefore, 95% confidence interval for the mean time spent studying for the final exam for students taking introductory psychology at this university is [6.85 hours, 7.43 hours].

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2 years ago

Find 95% of 83. do not round your answer.

MissTica

Answer:

78.85%

Step-by-step explanation:

<3 branliest, 5 stars, and thanks

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2 years ago

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Ugo [173]

$3t-7=5t \ \ \ \ \ |\hbox{subtract 3t} \\
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3 years ago

8h + 16h -12 = 24h -12

lys-0071 [83]

To solve for h
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Answer:

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30=2w

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