Answer:
Solution given:
f(x)=x²
g(x)=x+5
h(x)=4x-6
now
23:
(fog)(x)=f(g(x))=f(x+5)=(x+5)²=x²+10x+25
24:
(gof)(x)=g(f(x))=g(x²)=x²+5
25:
(foh)(x)=f(h(x))=f(4x-6)=(4x-6)²=16x²-48x+36
26:
(hof)(x)=h(f(x))=h(x²)=4x²-6
27;
(goh)(x)=g(h(x))=g(4x-6)=4x-6+5=4x-1
28:
(hog)(x)=h(g(x))=h(x+5)=4(x+5)-6=4x+20-6=4x-14
Let's look at it like this:
5/10+1/5 = (5/10) + (1/5)
5/10 = 0,5
1/5 = 0,2
so it's 5/10 + 1/5 = (5/10) + (1/5) = 0,5 + 0,2 = <u>0,7 </u>
Answer:
1×-5= -5squared =25+(4×-4squared)=25+(-16)=9
Question:
What is the common ratio between successive terms in the sequence?
27, 9, 3, 1
Answer:
common ratio = 
Step-by-step explanation:
In a geometric progression, the common ratio, r, is the ratio of a term in the sequence to a preceding term in that same sequence. In other words, the common ratio is found by dividing a term by the term just before it. For example, if the geometric sequence is:
a, b, c, d...
The common ratio is found by any of the following;
r =
----------(i)
r =
-----------(ii)
r =
------------(iii)
Any of equations (i) through (iii) will give the common ratio of the sequence.
============================================================
Now, from the question, the given sequence is;
27, 9, 3, 1
To get the common ratio, just divide the second term (9) by the first term (27) i.e
r =
= 
OR
You can also divide the third term (3) by the second term (9). i.e
r =
= 
OR
You can choose to divide the fourth term (1) by the third term (3). i.e
r = 
Which ever adjacent terms you choose gives you the same result. Therefore, the common ratio of the given sequence is 
Y = 3/4x - 5/2...subtract 3/4x from both sides
-3/4x + y = -5/2....multiply both sides by -4
3x - 4y = 10 <===
==============
x + 4y = 12....subtract x from both sides
4y = -x + 12...divide both sides by 4
y = 1/4x + 3 <==
==============
y = 1/2x.....this will be going thru the origin (0,0)....so start at (0,0)...and since it has a slope of 1/2, go up 1 space and to the right 2 spaces...plot that point...then up 1 and to the right 2...plot that point...keep doing this....and then just connect ur plotted points and u will have ur line