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IgorC [24]
3 years ago
5

What is one layer of bone

Physics
2 answers:
devlian [24]3 years ago
8 0

Answer:

The outer surface of bone is called the periosteum (say: pare-ee-OSS-tee-um). It's a thin, dense membrane that contains nerves and blood vessels that nourish the bone. The next layer is made up of compact bone. This part is smooth and very hard.

Pie3 years ago
6 0

Periosteum. anatomy. Periosteum, dense fibrous membrane covering the surfaces of bones, consisting of an outer fibrous layer and an inner cellular layer (cambium). The outer layer is composed mostly of collagen and contains nerve fibres that cause pain when the tissue is damaged.Answer:

Explanation:

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The red light from a helium-neon laser has a wavelength of 721.4 nm in air. Find the speed, wavelength, and frequency of helium-
saveliy_v [14]

Answer:

(a) the speed of helium-neon laser light in air is 3 x 10⁸ m/s

     the wavelength of helium-neon laser light in air is 721.4 nm

     the frequency of helium-neon laser light in air is 415.86 THz

(b)  the speed of helium-neon laser light in water is 2.26 x 10⁸ m/s

     the wavelength of helium-neon laser light in water is  542.4nm

     the frequency of helium-neon laser light in water is    416.67THz

(c) the speed of helium-neon laser light in glass is 2 x 10⁸ m/s

    the wavelength of helium-neon laser light in glass is  480.9nm

    the frequency of helium-neon laser light in glass is  415.88THz

From the results above, it can be seen that speed of the light is directly proportional to its wavelength, while the frequency of the light remained fairly constant for the different media.

Explanation:

Part (a) the speed, wavelength, and frequency of helium-neon laser light in air

Given;

wavelength of helium-neon laser light in air, λ = 721.4 nm

speed of light in air, v = 3 x 10⁸ m/s

v = f λ

where;

f is the frequency of helium-neon laser light in air

f = \frac{v}{\lambda} = \frac{3*10^8}{721.4 *10^{-9}} =4.1586*10^{14} \ Hz

f = 415.86 THz

Part (b) the speed, wavelength, and frequency of helium-neon laser light in water

refractive index of water = 1.33

Refractive \ index \ of \ water =\frac{speed \ of \ light \ in \ air}{speed \ of \ light \ in \ water} = \frac{wavelength \ of \ light \ in \ air}{wavelength \ of \ light \ in \ water}

speed \ of \ light \ in \ water = \frac{speed \ of \ light \ in \ air}{Refractive \ index \ of \ water} \\\\speed \ of \ light \ in \ water = \frac{3*10^8}{1.33} = 2.26 *10^8 \ m/s

Again;

wavelength \ of \ light \ in \ water = \frac{wavelength \ of \ light \ in \ air}{Refractive \ index \ of \ water} \\\\wavelength \ of \ light \ in \ water = \frac{721.4 \ nm}{1.33} = 542.4 \ nm

f = \frac{v}{\lambda} = \frac{2.26*10^8}{542.4 *10^{-9}} =4.1667*10^{14} \ Hz

f = 416.67 THz

Part (c) the speed, wavelength, and frequency of helium-neon laser light in glass

Refractive index of glass = 1.5

speed \ of \ light \ in \ glass = \frac{speed \ of \ light \ in \ air}{Refractive \ index \ of \ glass} \\\\speed \ of \ light \ in \ glass = \frac{3*10^8}{1.5} = 2 *10^8 \ m/s

Also;

wavelength \ of \ light \ in \ glass = \frac{wavelength \ of \ light \ in \ air}{Refractive \ index \ of \ glass} \\\\wavelength \ of \ light \ in \ glass = \frac{721.4 \ nm }{1.5} = 480.9 \ nm

f = \frac{v}{\lambda} = \frac{2*10^8}{480.9 *10^{-9}} =4.1588*10^{14} \ Hz

f = 415.88 THz

5 0
3 years ago
Read 2 more answers
As a summer intern assigned to the Olympics Kayaking committee, you need to determine the speed of water flowing through a rapid
Nookie1986 [14]

Answer:

11.56521 m/s

Explanation:

A_1 = Area of first section = 14\times 2

A_2 = Area of second section = 5\times 0.92

V_1 = Velocity in first section = 1.9 m/s

V_2 = Velocity in second section

From the continuity equation we get

A_1V_1=A_2V_2\\\Rightarrow V_2=\dfrac{A_1V_1}{A_2}\\\Rightarrow V_2=\dfrac{14\times 2\times 1.9}{5\times 0.92}\\\Rightarrow V_2=11.56521\ m/s

The speed of the river through the section of rapids is 11.56521 m/s

5 0
2 years ago
The density of a substance is 3.4 g cm-3. Its relative density relative to another substance is 2.0. what is the density of the
ankoles [38]

Answer:

1.7 g/cm³

Explanation:

Given that:

Density of substance = 3.4 g/cm³

Relative density to another substance = 2

Density of second substance=?

Let density of second substance = x

Relative density = density of substance / density of second substance

Relative density = density of substance / x

2.0 = 3.4g/cm³ / x

2 * x = 3.4 g /cm³

x = 3.4 g/cm³ ÷ 2

x = 1.7 g/cm³

5 0
2 years ago
1. It takes 120 minutes for a man to ride his bicycle up the road to Alpe d'Huez in France. The vertical height of the climb is
zloy xaker [14]
To1. PE = mgh

PE potential energy
m mass
g 9.81
h height

P = PE / t

P power
t time


3 0
3 years ago
Please help this determines my grade! A 25 V battery is connected into a circuit with two resistors in series. One resistor has
Verdich [7]

The answer is V=25(7.5/(7.5+5)).

This is the voltage divider equation.

I hope this helps!

6 0
3 years ago
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