The correct answer is 1.07m.
The area surrounding an electric charge where its impact may be felt is known as the electric field. When another charge enters the field, the presence of an electric field may be felt. The electric field will either attract or repel the charge depending on its makeup. Any electric charge has a property known as the electric field. The charge and electrical force working in the field determine the strength or intensity of the electric field.
Here, is the charge per unit length, r is the distance from the wire, and
is the free space permittivity ε_0. Electric field due to the long straight wire is,
E= λ/2πε_0r
Rearrange the equation for r.
r=λ/2πε_0E
Substitute 2.41 N/C for E,
E=1.44×10^-10C/m
λ=8.85×10^-12C^2/Nm^2
r=(1.44×10^-10C/m)/(2(3.14)(8.85×10^-12C^2/Nm^2)(2.41N/C))
r=1.07m
At a distance of 1.07 m the magnitude of electric field is 2.41 N/C.
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The final velocity before takeoff is 104.96 m / s.
<u>Explanation:</u>
The last velocity of a given object over some time defines the final velocity. The final velocity of the object is given by the product of acceleration and time and adding this product to the initial velocity.
To calculate the final velocity,
V = u + at
where v represents the final velocity,
u represents the initial velocity,
a represents the acceleration
t represents the time taken.

v = 104.96 m / s.
Answer:
h = 5.05 m
Explanation:
given,
mass of pole vaulter, m = 64 Kg
speed of the vaulter,V = 10.2 m/s
horizontal component of velocity in air, v = 1 m/s
height of the jump,h = ?
using energy conservation


initial height of the vaulter is equal to zero.



h = 5.05 m
height of the jump is equal to 5.05 m.
Answer:
A. The horizontal velocity vector points to the right & equals v cos θ.
Explanation:
The motion describes a parabolic path, where the horizontal speed is constant and the horizontal velocity vector always points to the right and equals v*cos θ.
Explanation:
It is given that,
Length of the simple pendulum, l = 36.9 cm = 0.369 m
If it takes 14.2 s to complete 10 oscillations, 
(a) The time period of the simple pendulum is given by :




(b) On the surface of moon, 
At earth, 

As the value of g is less on the moon, so the time period on the moon increases.
(c) The time period on the earth, T = 3 s
On earth,
..............(1)
On moon, 
..............(2)
On solving equation (1) and (2),
T' = 18.03 s
Hence, this is the required solution.