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Anna71 [15]
3 years ago
10

A student walks to the right 25-m along the 800 hall in 15-s. They turn around and walk 15-m to the left in 8.0-s. Calculate the

average speed and the average velocity
Physics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

Explanation:

Total distance covered  = 25 + 15 = 40 m

Total time = 15 + 8 = 23 s

Average speed = total distance covered / total time

= 40 / 23

= 1.74 m / s

Total displacement = 25 - 15 = 10 m

Total time = 15 + 8 = 23 s

Average velocity = total displacement / total time

= 10 / 23

= .434 m / s to the right .

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Explanation:

Average speed of the car A is v_{A} =\frac{x_{A} }{t_{A} } (Equation A) and Average speed of the car B is v_{B} =\frac{x_{B} }{t_{B} } (Equation B), where x_{A} and x_{B} are the distances and t_{A} and t_{B} are the times at which are travelling the cars A and B respectively.

We have to convert the time to the correct units:

1 hour and 36 minutes = 96 minutes

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From the diagram (Please see the attachment), we can see that at the time they meet, we have:

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From Equation A and C, we have:

\frac{208-x}{1.6}+10 = \frac{x}{1.6}

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v_{B}  = \frac{208miles-112miles}{1.6h}

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v_{B}  = 60 miles per hour

3 0
3 years ago
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