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Anna71 [15]
3 years ago
10

A student walks to the right 25-m along the 800 hall in 15-s. They turn around and walk 15-m to the left in 8.0-s. Calculate the

average speed and the average velocity
Physics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

Explanation:

Total distance covered  = 25 + 15 = 40 m

Total time = 15 + 8 = 23 s

Average speed = total distance covered / total time

= 40 / 23

= 1.74 m / s

Total displacement = 25 - 15 = 10 m

Total time = 15 + 8 = 23 s

Average velocity = total displacement / total time

= 10 / 23

= .434 m / s to the right .

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In which situation is a person doing work on an object?
Marianna [84]

Answer : When a person applies force and covers distance then the person is doing work on an object.

6 0
2 years ago
Read 2 more answers
A child with mass of 25 kg gets into a toy car with mass of 80 kg on a playground, causing it to sink on its springs (with effec
Bess [88]

Answer:

The frequency of the oscillation is 0.9Hz

Explanation:

This problem bothers on simple harmonic motion of a spring

Given data

Mass of the child m= 25kg

Spring constant k=791 N/m

Amplitude a= 31cm

But the period of the motion as a result of the adults sholve is expressed as

T=2π√m/k

T=2*3.142√25/791

T=6.284√0.031

T=6.284*0.176

T=1.11 sec

But frequency F=1/T

F=1/1.11

F=0.9Hz

4 0
2 years ago
A generator produces 60 A of current at 120 V. The voltage is usually stepped up to 4500 V by a transformer and transmitted thro
aalyn [17]

Answer:

The percentage power lost in the transmission line if the voltage not stepped up is 50%.

Explanation:

Given that,

Current = 60 A

Voltage = 120 V

Resistance = 1.0 ohm

We need to calculate the power

Using formula of power

P=I\times V

Where,I =current

V = voltage

Put the value into the formula

P=60\times120

P=7200\ W

We need to calculate the percentage power lost in the transmission line

If the voltage is not stepped up

Then, the power loss

P'=I^2\times R

Put the value into the formula

P'=(60)^2\times1

P'=3600\ W

The percentage power loss P''

P''=\dfrac{P'}{P}\times100=\dfrac{3600}{7200}\times100

P''=50\%

Hence, The percentage power lost in the transmission line if the voltage not stepped up is 50%.

5 0
2 years ago
An object is 15 cm in front of a diverging lens with a
Rainbow [258]

A) See ray diagram in attachment (-6.0 cm)

By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = -10 cm is the focal length (negative for a diverging lens)

p = 15 cm is the distance of the object from the lens

Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

q=\frac{1}{-0.167 cm^{-1}}=-6.0 cm

B) The image is upright

As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:

h_i = - h_o \frac{q}{p}

where h_i, h_o are the size of the image and of the object, respectively.

Since q < 0 and p > o, we have that h_i >0, which means that the image is upright.

C) The image is virtual

As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.

This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

4 0
3 years ago
A coil with 55 loops has its flux change from 0 Wb to 0.0266 Wb in a certain amount of time, generating 5.22 V of EMF. How much
Eduardwww [97]

Answer:

0.280 s

Explanation:

I set it up as 5.22=(55)(0.0266)/x and then solved for x to be 2.80.

4 0
2 years ago
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