Along the flow direction, the boundary layer's thickness varies. For ReT values between 260 and 780, the boundary layer thickness—defined as the depth at which the normalized concentration has a value of 1/e—ranges between 800 and 250 m.
<h3>What is the Boundary layer?</h3>
- A boundary layer is the thin layer of fluid that forms immediately around a bounded surface in physics and fluid mechanics as a result of the fluid flowing along the surface.
- A no-slip boundary condition is created as a result of the fluid and wall interaction (zero velocity at the wall).
- After that, the flow velocity above the surface steadily rises until it reaches the bulk flow velocity again.
- The term "velocity boundary layer" refers to the thin layer of fluid whose velocity has not yet recovered to that of the main flow.
<h3>What purpose does a boundary layer serve?</h3>
- Because it is on the fluid's boundary, engineers refer to this layer as the boundary layer.
- Many aerodynamics issues, such as wing stall, skin friction drag on an object, and the heat transfer that takes place in high-speed flight, depend heavily on the specifics of the flow within the boundary layer.
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Answer:
5.5 N at 50.8° north of west.
Explanation:
To find the resultant of these forces, we have to resolve each force along the x- and y-direction, then find the components of the resultant force, and then calculate the resultant force.
The three forces are:
(east)
(west)
(at 60° north of west)
Taking east as positive x-direction and north as positive y-direction, the components of the forces along the 2 directions are:



Threfore, the components of the resultant force are:

Therefore, the magnitude of the resultant force is

And the direction is:

And since the x-component is negative, it means that this angle is measured as north of west.
Answer:a b c
Explanation: I’m not sure tho
Answer:
t = 12s
Explanation:
Given:
v-initial = 0 m/s
x = 360 m
a = 5.0 m/s^2
Solve:
x = (v-initial)t + 1/2(a*t^2)
360 = 0t + 1/2 (5.0t^2)
360 = 2.5 t^2
144 = t^2
t = sqrt(144) = 12
Therefore, it takes 12 seconds.