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DENIUS [597]
3 years ago
10

Which of the following best describes chemical weathering?

Physics
2 answers:
dexar [7]3 years ago
5 0

Answer:

<h3>ir id n becuswe ig gyst makres sensre</h3>

Explanation:

Lelu [443]3 years ago
3 0

Answer: it's D

Explanation:

it's the last answer I'm taking the test right now and I got it right so hope this helps

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A whale comes to the surface to breathe and then dives at an angle of 20.0 ∘ below the horizontal. If the whale continues in a s
charle [14.2K]

Answer:

It is 68.404 m deep.

Explanation:

The motion of the whale can be seen in the form of a right-angle triangle.

Angle of deviation = 20°

We know that, sinФ = Perpendicular/ Hypotenuse.

Here, hypotenuse = 200 m

Depth is perpendicular that we have to find.

sin(20°) = Depth/200

Depth = sin(20°) * 200 = 68.404 meters.

8 0
4 years ago
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In order for a reaction to begin what is required
Andrew [12]

Activation energy?

are there multiple choices?

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3 years ago
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During each cycle of operation a refrigerator absorbs 56 cal from the freezer compartment and expels 81 cal tothe room. If one c
Alexandra [31]

Answer:

138.18 minutes

Explanation:

L_v = Latent heat of water at 0°C = 80 cal/g

m = Mass of water = 570 g

Heat removed for freezing

Q=mL_v\\\Rightarrow Q=570\times 80\\\Rightarrow Q=45600\ cal

Let N be the number of cycles and each cycle removes 56 cal from the freezer.

So,

55\times N=45600\\\Rightarrow N=\frac{45600}{55}

Each cycle takes 10 seconds so the total time would be

\frac{45600}{55}\times \frac{10}{60}=138.18\ minutes

The total time taken to freeze 138.18 minutes

6 0
3 years ago
Calculate the pressure, in atmospheres, exerted by each of the following:
gregori [183]

Answer:

a) 14.2 atm

b) 4.46 atm

c) 1.06 atm

Explanation:

For an ideal gas,

PV = nRT

P = pressure of the gas

V = volume occupied by the gas

n = number of moles of the gas

R = molar gas constant = 0.08206 L.atm/mol.K

T = temperature of the gas in Kelvin

a) For HF,

P =?, V = 2.5L, n = 1.35 moles, T = 320K

P = 1.35 × 0.08206 × 320/2.5

P = 14.2 atm

b) For NO₂

P =?, V = 4.75L, n = 0.86 moles, T = 300K

P = 0.86 × 0.08206 × 300/4.75

P = 4.46 atm

c) For CO₂

P =?, V = 5.5 × 10⁴ mL = 55L, n = 2.15 moles, T = 57°C = 330K

P = 2.15 × 0.08206 × 330/55

P = 1.06 atm

4 0
4 years ago
Four students were loading boxes of food collected during a food drive. The force that each student exerted while lifting and th
Fudgin [204]

Answer:

it is B

Explanation:

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7 0
3 years ago
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