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Lorico [155]
3 years ago
11

You are asked to determine the density of a liquid. What lab equipment is most helpful to find density of the liquid?

Physics
2 answers:
crimeas [40]3 years ago
7 0
The answer is D, the graduated cylinder and a triple beam-balance
AnnyKZ [126]3 years ago
6 0
D. The graduated cylinder is used to find the volume, and triple beam balance is used to find the mass.
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If the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave?
GaryK [48]

Answer:

f = 614.28 Hz

Explanation:

Given that, the length of the air column in the test tube is 14.0 cm. It can be assumed that the speed of sound in air is 344 m/s. The test tube is a kind of tube which has a closed end. The frequency in of standing wave in a closed end tube is given by :

f=\dfrac{nv}{4l}

f=\dfrac{1\times 344}{4\times 0.14}

f = 614.28 Hz

So, the frequency of the this standing wave is 614.28 Hz. Hence, this is the required solution.

4 0
4 years ago
100 g of Ice at -10°C is added into a
Andrei [34K]

Answer:

The mass of the juice responsible for melting the ice is 949.043 grams.

Explanation:

By the First Law of Thermodynamics, we understand that juice releases heat to the ice, which turns into water under the assumption that interactions between the ice-juice system and surroundings are negligible and energy processes are done in steady-state. Since juice is done with water, its specific heat will be taken as of the water. The process is described by the following formula:

m_{i} \cdot [c_{i}\cdot (T_{1}-T_{2}) - L_{f} + c_{w}\cdot (T_{2}-T_{3})] + m_{w} \cdot  c_{w}\cdot (T_{4}-T_{3}) = 0 (1)

Where:

m_{i} - Mass of ice, in grams.

m_{w} - Mass of the juice, in grams.

c_{i} - Specific heat of ice, in joules per gram-degree Celsius.

c_{w} - Specific heat of water, in joules per gram-degree Celsius.

L_{f} - Latent heat of fusion, in joules per gram.

T_{1} - Initial temperature of ice, in degrees Celsius.

T_{2} - Melting point of water, in degrees Celsius.

T_{3} - Final temperature of the ice-juice system, in degrees Celsius.

T_{4} - Initial temperature of the juice, in degrees Celsius.

If we know that m_{i} = 100\,g, c_{i} = 2.090\,\frac{J}{g\cdot ^{\circ}C}, c_{w} = 4.18\,\frac{J}{g\cdot ^{\circ}C}, L_{f} = 334\,\frac{J}{g}, T_{1} = -10\,^{\circ}C, T_{2} = 0\,^{\circ}C, T_{3} = 10\,^{\circ}C and T_{4} = 20\,^{\circ}C, then the mass of the juice is:

m_{w} = \frac{m_{i}\cdot [c_{i}\cdot (T_{1}-T_{2}) - L_{f} + c_{w}\cdot (T_{2}-T_{3})]}{c_{w} \cdot (T_{3}-T_{4})}

m_{w} = \frac{(100\,g)\cdot  \left[\left(2.090\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C) - 334\,\frac{J}{g} +\left(4.18\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C)  \right]}{\left(4.180\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C)}

m_{w} = 949.043\,g

The mass of the juice responsible for melting the ice is 949.043 grams.

5 0
3 years ago
Choose the correct words from the box to complete the definition of resistance.
zzz [600]

Answer:

Opposition of passing a electric circuit

6 0
3 years ago
What net force would be required for a 50.5 kg wolf to accelerate at 5.0 m/s^2
Basile [38]

Answer:

\boxed {\boxed {\sf 252.5 \ Newtons }}

Explanation:

Force is the push or pull on object that can cause different things, like acceleration. According to Newton's 2nd Law of Motion, it is the product of mass and acceleration.

F=m*a

The mass of the wolf is 50.5 kilograms and the acceleration is 5.0 meters per square second. Therefore:

  • m= 50.5 \ kg
  • a= 5.0 \ m/s^2

Substitute the values into the formula.

F= 50.5 \ kg * 5.0 \ m/s^2

Multiply.

F=252.5 \ kg*m/s^2

  • 1 kilogram meter per square second is equal to 1 Newton.
  • Our answer of 252.5 kg*m/s² is equal to 252.5 Newtons.

F= 252.5 \ N

The force required is <u>252.5 Newtons</u>.

4 0
3 years ago
If a force of 5 n to left and 9 n to right act on a object what is the net force
emmainna [20.7K]
4 n to the right is the net force
7 0
3 years ago
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