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Lorico [155]
3 years ago
11

You are asked to determine the density of a liquid. What lab equipment is most helpful to find density of the liquid?

Physics
2 answers:
crimeas [40]3 years ago
7 0
The answer is D, the graduated cylinder and a triple beam-balance
AnnyKZ [126]3 years ago
6 0
D. The graduated cylinder is used to find the volume, and triple beam balance is used to find the mass.
You might be interested in
Velocity and Time
Murrr4er [49]

Answer:

h=112.35

Explanation:

becuase it had to

3 0
3 years ago
Beats are the difference in (a) Frequency (b) Amplitude (c) Intensity (d) None
sasho [114]

Answer:

Beats are the difference in frequency.

(a) is correct option.

Explanation:

Beat :

Beat is the difference of the frequency of two waves.

The difference in frequency is equal to the number of beat per second.

Amplitude :

Amplitude of the wave is the maximum displacement.

Frequency :

Frequency is the number oscillations of wave in per second.

Intensity :

Intensity is the power per unit area.

Hence, Beats are the difference in frequency.

7 0
3 years ago
How would local winds be affected if water and land release heat at the same time
BlackZzzverrR [31]
Local winds are driven by temperature differences in areas fairly close to each other. If water and land absorbed and released heat at the same rate, there wouldn't be any temperature differences and nothing to power local winds. See the related link for further information.
8 0
3 years ago
Finding the area of a trapezoid on a velocity versus time graph will tell you
julsineya [31]
The answer is c. velocity
6 0
2 years ago
Let’s look at a radio-controlled model car. Suppose that at time t1=2.0st1=2.0s the car has components of velocity vx=1.0m/svx=1
Nonamiya [84]

Answer:

a_x=6\ \text{m/s}^2 and a_y=0\ \text{m/s}^2

Magnitude of accleration is 6\ \text{m/s}^2 and the direction is 0^{\circ}

Explanation:

t_1=2\ \text{s}

v_x=1\ \text{m/s}

v_y=3\ \text{m/s}

t_2=2.5\ \text{s}

v_x=4\ \text{m/s}

v_y=3\ \text{m/s}

Average acceleration in the different axes

a_x=\dfrac{\Delta v_x}{\Delta t}\\\Rightarrow a_x=\dfrac{4-1}{2.5-2}\\\Rightarrow a_x=6\ \text{m/s}^2

a_y=\dfrac{\Delta v_y}{\Delta t}\\\Rightarrow a_y=\dfrac{3-3}{2.5-2}\\\Rightarrow a_y=0\ \text{m/s}^2

The components of the acceleration is a_x=6\ \text{m/s}^2 and a_y=0\ \text{m/s}^2

The magnitude of acceleration

a=\sqrt{a_x^2+a_y^2}\\\Rightarrow a=\sqrt{6^2+0^2}\\\Rightarrow a=6\ \text{m/s}^2

Direction

\theta=\tan^{-1}\dfrac{a_y}{a_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{0}{6}\\\Rightarrow \theta=0^{\circ}

The magnitude of accleration is 6\ \text{m/s}^2 and the direction is 0^{\circ}.

7 0
2 years ago
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