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igor_vitrenko [27]
3 years ago
6

1+7 (1 - 3b)1+7 (1-3b)

Mathematics
1 answer:
Sergio [31]3 years ago
8 0
It is 16 minus 42b. (16 - 42b)
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Find the solution by elimination method. <br>Please Help. ​
love history [14]

Answer:

I'm newbie here

Step-by-step explanation:

Elimination Method.

4x + 6/y = 15 → step 1

6x - 8/y = 14 → step 2

so,

4x + 6/y = 15 |×6|

6x - 8/y = 14 |×4|

24x + 6/y(6) = 90

24x - 8/y(4) = 56

24x + 36/y = 90

24x - 32/y = 56

____________ _

68/y = 34

68 = 34y

34y = 68

y = 2

subsitution y = 2 to..

4x + 6/y = 15

4x + 6/2 = 15

4x + 3 = 15

4x = 12

x = 3

So, for x is 3, and for y is 2

5 0
3 years ago
Read 2 more answers
What is the answer to this 3a^2-9a
olchik [2.2K]
If i'm correct, the answer should be

-3a

hope this helped! 8)

4 0
3 years ago
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Given tantheta = 4/3 and pi &lt; theta &lt; 3pi/2; find cos2theta
Sidana [21]

Answer:

d. -7/25

Step-by-step explanation:

π<θ<3π/2  in third quadrant

tanθ = 4/3

sinθ = - 4/5

cosθ = - 3/5

cos 2θ = cos²θ - sin²θ = (- 3/5)² - (- 4/5)² = 9/25 - 16/25 = - 7/25

8 0
3 years ago
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Beneficial terms of trade are the terms or prices that are between the two parties' oppotunity costs
nevsk [136]

Answer:

Beneficial terms of trade or trading price between two parties are opportunity costs lower than the cost to manufacture them locally which benefits both parties. They must be less enough to cover the freight charges or additional service charges that may arise.

3 0
3 years ago
18 PTS! From the equation below, identify the slope and a point on the line. y−3=−2(x+1)
omeli [17]

<u>ANSWER:  </u>

The slope of the given equation is -2 and a point on the given line is (-1, 3)

<u>SOLUTION:</u>

Given, linear equation in two variables is y – 3 = -2(x + 1) ----- eqn (1)

We need to find the slope of the given equation and a point through which the given line passes.

Given equation is in the form of point slope form  .i.e \mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right) --- eqn 2

where,"m" is the slope of the line

\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) is point on that line.

Now, by comparing (1) and (2)

m = -2

x_{1}=-1

y_{1}=3

so, the slope of the given equation is -2  and a point on the given line is (-1, 3)

7 0
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