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disa [49]
3 years ago
8

Sodium chloride or table salt is a compound formed when sodium loses its valence electron to chlorine. Which type of bond format

ion takes place in sodium chloride?
A. Covalent bond
B. Ionic bond
C. Metallic bond
Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

the answer is b so the second option

Alenkasestr [34]3 years ago
4 0
<span>The answer is the option B. ionic bond. The ionic bond takes place when two ions of opposite charge (one positive and other negative) are bonded due to the electrostatic force between them. When sodium loses its valence electron it forms the positive ion (cation) Na+, and when chloride gains the electron lost by the sodium atom, it forms the negative ion (anion) Cl -, so these two ions form the ionic bond.</span>
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If 1.3 L of C3H8 combusts according to the equation below, how much CO2 will be produced?
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0.162 moles of CO₂ are produced by this reaction

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6 0
3 years ago
A buffer solution is made that is 0.347 M in H2C2O4 and 0.347 M KHC2O4.
irga5000 [103]

Answer:

1. pH = 1.23.

2. H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Explanation:

Hello!

1. In this case, for the ionization of H2C2O4, we can write:

H_2C_2O_4\rightleftharpoons HC_2O_4^-+H^+

It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:

pH=pKa+log(\frac{[base]}{[acid]} )

Whereas the pKa is:

pKa=-log(Ka)=-log(5.90x10^{-2})=1.23

The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:

pH=1.23+log(\frac{0.347M}{0.347M} )\\\\pH=1.23+0\\\\pH=1.23

2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:

n_{acid}=0.347mol/L*1.00L=0.347mol\\\\n_{acid}^{remaining}=0.347mol-0.070mol=0.277mol

It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:

H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Which is also shown in net ionic notation.

Best regards!

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