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disa [49]
3 years ago
8

Sodium chloride or table salt is a compound formed when sodium loses its valence electron to chlorine. Which type of bond format

ion takes place in sodium chloride?
A. Covalent bond
B. Ionic bond
C. Metallic bond
Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

the answer is b so the second option

Alenkasestr [34]3 years ago
4 0
<span>The answer is the option B. ionic bond. The ionic bond takes place when two ions of opposite charge (one positive and other negative) are bonded due to the electrostatic force between them. When sodium loses its valence electron it forms the positive ion (cation) Na+, and when chloride gains the electron lost by the sodium atom, it forms the negative ion (anion) Cl -, so these two ions form the ionic bond.</span>
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Answer:

18.018 seconds.

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Given that the half life of Manganese, Mn = 3 seconds. The initial sample mass = 90.0 gram, the final sample mass = 1.40 gram.

The general idea to the question is to look for the time it will take to decay from the initial mass that is 90 gram to 1.40 gram.

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J(t) = J(o) × (1/2)^t/t(hL).

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1.4 = 90 × (1/2)^ t/3.

1.4/90 = (1/2)^t/3.

t/3 = log(0.5) (1.4/90).

+Please note that the 0.5 of the log is at the subscript).

That is the base 0.5 logarithm of (1.4/90) 0.01556 is 6.0060141295.

t = 3 × 6.0060141295.

t = 18.018 seconds.

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What is the freezing point (in °C) of a 0.743 m
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3 years ago
Question 7 of 15
Crazy boy [7]

Answer: 0.4 moles

Explanation:

Given that:

Volume of gas V = 11L

(since 1 liter = 1dm3

11L = 11dm3)

Temperature T = 25°C

Convert Celsius to Kelvin

(25°C + 273 = 298K)

Pressure P = 0.868 atm

Number of moles N = ?

Note that Molar gas constant R is a constant with a value of 0.00821 atm dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

0.868atm x 11dm3 = n x (0.00821 atm dm3 K-1 mol-1 x 298K)

9.548 atm dm3 = n x 24.47atm dm3mol-1

n = (9.548 atm dm3 / 24.47atm dm3 mol-1)

n = 0.4 moles

Thus, there are 0.4 moles of the gas.

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3 years ago
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Answer:

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3 years ago
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