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3 years ago

How many moles of oxygen atoms are present in 3 moles of sulfur dioxide?

2 answers:

6 0

There are two moles of oxygen in one mole of sulfur dioxide, hence the molecular formula being SO2. Therefore, the number of oxygen moles will be double the number of moles of sulfur dioxide.

3 moles SO2 * (2 moles O)/(1 mole SO2) = 6 moles Oxygen atoms

hammer [34]3 years ago

4 0

Answer: 6moles of oxygen

Explanation:

The chemical formula for sulphurdioxide is SO2.

3 moles of sulphurdioxide will be 3SO2.

In sulphurdioxide, there is presence of 2 atoms of oxygen (O2). Therefore to get the total number of moles of oxygen in 3moles of SO2, we will multiply the number of atom of oxygen present (2) with the number of moles of SO2 compound (3).

That will be equivalent to 2×3 = 6moles of oxygen.

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A chemist mixes 1.00 g CuCl2 with an excess of (NH4)2HPO4 in dilute aqueous solution . He measures the evolution of 670 J of hea

kaheart [24]

Answer:

$\Delta H$ will be 90054 J

Explanation:

Number of moles = (mass)/(molar mass)

Molar mass of $CuCl_{2}$ = 134.45 g/mol

So, 1.00 g of $CuCl_{2}$ = $\frac{1.00}{134.45}mol$ of $CuCl_{2}$ = 0.00744 mol of $CuCl_{2}$

0.00744 mol of $CuCl_{2}$ produces 670 J of heat

So, 1 mol of $CuCl_{2}$ produces $\frac{670}{0.00744}J$ of heat or 90054 J of heat

4 0

3 years ago

What is quantitative and qualitative

jenyasd209 [6]

Quantitative is a description in numbers , and qualitative is a description with words

8 0

3 years ago

An unknown compound has a percent composition of 52.10% potassium, 15.8% carbon, and 32.1% oxygen. The molar mass of the compoun

lianna [129]

To determine the empirical formula and the molecular formula of the compound, we assume a basis of the compound of 100 g. We do as follows:

Mass Moles
K 52.10 52.10/39.10 = 1.33 1.33/1.32 ≈ 1
C 15.8 15.8/12 = 1.32 1.32/1.32 ≈ 1
O 32.1 32.1 / 16 = 2.01 2.01/1.32 ≈ 1.5

The empirical formula would most likely be KCO.
The molecular formula would be K2C2O3.

4 0

3 years ago

Read 2 more answers

How much positive charge is in 0.7 kg of lithium? with each atom having 3 protons and 3 electrons. The elemental charge is 1.602

hichkok12 [17]

Explanation:

As a neutral lithium atom contains 3 protons and its elemental charge is given as $1.602 \times 10^{-19} C$ . Hence, we will calculate its number of moles as follows.

Moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.7 \times 1000 g}{7 g/mol}$

= 100 mol

According to mole concept, there are $6.023 \times 10^{23}$ atoms present in 1 mole. So, in 100 mol we will calculate the number of atoms as follows.

No. of atoms = $100 \times 6.023 \times 10^{23}$

= $6.023 \times 10^{25}$ atoms

Since, it is given that charge on 1 atom is as follows.

$3 \times 1.602 \times 10^{-19}C$

= $4.806 \times 10^{-19}C$

Therefore, charge present on $6.023 \times 10^{25}$ atoms will be calculated as follows.

$6.023 \times 10^{25} atoms \times 4.806 \times 10^{-19} C$

$28.95 \times 10^{6}C$

Thus, we can conclude that a positive charge of $28.95 \times 10^{6}C$ is in 0.7 kg of lithium.

3 0

3 years ago

What is the scaling factor if the molar mass of

Step2247 [10]

Answer:

The scaling factor is 5.

Explanation:

Hello there!

In this case, since the scaling factor is defined as the ratio of the molar mass of the molecular formula (complete) to the empirical formula (simplified), it is possible to compute it for the empirical formula of CH2O whose molar mass is 30 g/mol (12+2+16) as shown below:

$sf=150/30=5$

Therefore, we can also infer that the molecular formula would be:

$C_5H_1_0O_5$

Best regards!

6 0

3 years ago