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3 years ago

Changing the number of protons in an atom makes A. an ion B. an isotope

1 answer:

5 0

A. an ion

The atom gains a net electrical charge if the number of protons and electrons are not equal which makes it an ion.

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For which of the processes below will δs be a positive number? 1) ch4(g) → ch4(l) 2) n2h4(g) → n2(g) + 2h2(g) 3) h2o(s) → h2o(g)

Shalnov [3]

The entropy of the gaseous substance is more in comparison to the liquid or solid form of the same substance at same temperature and pressure conditions.

More is the number of particles more will be the entropy of the system.

In the first chemical reaction, CH₄ (g) → CH₄ (l)

Since, the reactants are in gaseous phase and the products are in liquid phase, the entropy is decreasing during the reaction.

In the second chemical reaction,

N₂H₄ (g) → N₂ (g) + 2H₂ (g)

Since, one mole of the reactant in gaseous phase is decomposing to produce three moles of product in gaseous phase, the entropy is increasing during the reaction.

In the third chemical reaction, H₂O (s) → H₂O (g)

Since, the reactant is in solid phase and product are in gaseous phase. The entropy is increasing during the reaction.

Thus, the entropy is increasing in the 2nd and 3rd reactions.

3 0

3 years ago

The polyatomic nitrate ion (NO3−) is present in both the products and the reactants of the chemical equation shown below.

Diano4ka-milaya [45]

Answer:

There is one nitrate ion in the products, and two in the reactants of this equation.

Explanation:

1: We know a nitrate ion has the formula $NO_{3}^{-$ , so we just need to count how many of them are on each side of the equation.

2: To find how many are in the reactants of the equation, you look at the left hand side (before the arrow). You can see the section $(NO_{3} )_{2}$ , which shows that there are two nitrate ions in the reactant side (as seen by the little 2).

3: To find how many are on the products side, you do the same thing - this time there is only one $NO_{3}^{-$ in the lithium nitrate.

So, there is one nitrate ion in the products, and two in the reactants of this equation.

7 0

3 years ago

Read 2 more answers

A 0.5 mol sample of he(g) of ne(g) are placed separately in two 10.0 l rigid containers at 25°c. each container has a pinhole op

Serjik [45]

The movement of gases through pinhole is called effusion and the effusion rate indirectly proportional to the molar mass of gas

The lighter mass gas effuses faster than the heavier one
so He(g) will escapes faster and it will move with higher average speed because it has less mass than Ne(g)

7 0

3 years ago

A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in

In-s [12.5K]

Answer:

3.6667

Explanation:

For helium gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 3.0 L

V₂ = 9.0 L

P₁ = 5.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${5.6}\times {3.0}={P_2}\times {9.0} atm$

${P_2}=\frac {{5.6}\times {3.0}}{9.0} atm$

${P_1}=1.8667\ atm$

The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm

For Neon gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${3.6}\times {4.5}={P_2}\times {9.0} atm$

${P_2}=\frac {{3.6}\times {4.5}}{9.0} atm$

${P_1}=1.8\ atm$

The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm

Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.

6 0

3 years ago

What is the reason why carbonated beverages be kept cold?

Makovka662 [10]

Option A) Decreased temperature keeps gases like carbon dioxide dissolved.

Carbonation is made with CO2 which is also know as liquid carbonic. The low temperature favors higher solubility of CO2 in water

3 0

3 years ago