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3 years ago

Changing the number of protons in an atom makes A. an ion B. an isotope

1 answer:

5 0

A. an ion

The atom gains a net electrical charge if the number of protons and electrons are not equal which makes it an ion.

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Please I don’t get this at all someone help

ohaa [14]

I think it’s 7.41 because you count up all the atoms and find out how many are x (the large grey ones) and you do 2/27 x 100 which gives you 7.41 :) (sorry if i counted wrong it’s kinda hard)

6 0

3 years ago

An aqueous solution of ____ will produce a basic solution.

Anastasy [175]

NaClO, K2CO3, and NaF will form basic soltions.

6 0

4 years ago

Read 2 more answers

How many grams of hydrogen gas would be produced from the use of 9.5 moles of aluminum

DIA [1.3K]

Answer:

Identify one disadvantage to each of the following models of electron configuration:

Dot structures

Arrow and line diagrams

Written electron configurations

Explanation:

Identify one disadvantage to each of the following models of electron configuration:

Dot structures

Arrow and line diagrams

Written electron configurations

8 0

3 years ago

Democritius thought that

andre [41]

Atoms because electrons, neutrons and protons are in a atom

6 0

3 years ago

Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib

Dvinal [7]

Answer: The value of $K_c$ for the final reaction is $7.16\times 10^{25}$

Explanation:

The given chemical equations follows:

Equation 1: $H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1$

Equation 2: $HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2$

The net equation follows:

$S^{2-}(aq.)+2H^+(aq.)\rightleftharpoons H_2S(aq.);K_c$

As, the net reaction is the result of the addition of reverse of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of inverse of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c=\frac{1}{K_1}\times \frac{1}{K_2}$

We are given:

$K_1=9.57\times 10^{-8}$

$K_2=1.46\times 10^{-19}$

Putting values in above equation, we get:

$K_c=\frac{1}{(9.57\times 10^{-8})}\times \frac{1}{(1.46\times 10^{-19})}=7.16\times 10^{25}$

Hence, the value of $K_c$ for the final reaction is $7.16\times 10^{25}$

5 0

3 years ago