Answer:
Step-by-step explanation:
you can start by factoring x
x(2x³-x²-18x+9)
you can group terms in parentheses strategicly
x(2x³-18x-x²+9)=x[2x(x²-9)-(x²-9)]
now we can factor x²-9
x(x²-9)(2x-1)
factor the diference of two squares x²-9=x²-3²
x(x-3)(x+3)(2x-1)
so the roots are found by using the zero product rule
x(x-3)(x+3)(2x-1)=0 will give
x=0, x-3=0 so x=3, x+3=0 so x=-3, 2x-1=0 so x=1/2
from left to right
-3, 0, 1/2, 3
