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3 years ago

Write the equation. 5 more than a number times 2 is 2

Mathematics

1 answer:

suter [353]3 years ago

8 0

$(5 +n)\cdot2 = 2$

$3(2 -n) > 7$

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Someone please help me ASAP!

loris [4]

It would be (-5,-1) yw

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3 years ago

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(4x + 3)(4x - 3)<br> Help pls

tekilochka [14]

Answer:

$16x^2-9$

Step-by-step explanation:

$\left(4x+3\right)\left(4x-3\right)$

We´ll <u>Apply Difference Two Squares Formula:</u>

$\left(a+b\right)\left(a-b\right)=a^2-b^2$

$\longmapsto$ $\left(4x+3\right)\left(4x-3\right)$

$\longmapsto$ $\left(4x\right)^2-3^2$

<u>Apply exponent rule</u>:

$\left(a\times \:b\right)^n=a^nb^n$

$\longmapsto$ $4^2x^2-3^2$

$\longmapsto$ $16x^2-9$

_________________________

6 0

3 years ago

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Write 108.92 in expanded form.

Vlada [557]

Answer:

1.0892*10²

Step-by-step explanation:

1.0892*10²

5 0

3 years ago

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Let g(x) = root of 4x and f(x) = 3x^3 + 8x^2 , what is the expression of the compound h(x) = g(f(x)) ?

Nitella [24]

The composite function as shown is $g(f(x)) =\sqrt{12x^3+32x^2}$

<h3>Composite functions</h3>

Given the following fnctions

$f(x) = 3x^3 + 8x^2\\g(x) = \sqrt{4x}$

The composite function g(f(x)) is expressed as:

$g(f(x)) =g(3x^3 + 8x^2)\\g(f(x) )=\sqrt{4(3x^3 + 8x^2)} \\g(f(x)) =\sqrt{12x^3+32x^2}$

Hence the composite function as shown is $g(f(x)) =\sqrt{12x^3+32x^2}$

Learn more on composite function here: brainly.com/question/10687170

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3 years ago

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Solving for Matrices

laiz [17]

Answer:

option A

$\left[\begin{array}{ccc}9&-4&-5|9\\7&4&-4|-1\\6&-6&1|-5\end{array}\right]$

Step-by-step explanation:

Steps to write equations in augmented form

Step 1

Write the coefficients of the x-terms as the numbers down the first column

Step 2

Write the coefficients of the y-terms as the numbers down the second column

Step 3

Write the coefficients of the z-terms as the numbers down the third column

Step 4

Write the constants which are in the end of equation in fourth column

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