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4 years ago

Paula has a dog that weighs 3 times as much as Carla's dog. The total weight of the dogs is 68 pounds.

Mathematics

2 answers:

mr_godi [17]4 years ago

4 0

Answer:

Step-by-step explanation:

68/4=17

68-17=51

andriy [413]4 years ago

4 0

Answer:

Paula's dog weighs 51 pounds.

Carla's dog weighs 17 pounds.

17 times 3 equals 51.

Then 17 added to 51 equals to 68.

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Mamont248 [21]

13-4=9 and 7-4=3

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So the probability is 12/29

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4 years ago

RES Find (fºg)(1) Ax) = x2 - 1 g(x)= v a 0 c. 4. b. d. 18 Help pls

slava [35]

Answer:

Step-by-step explanation:

So we have the two functions:

$f(x)=x^2-1\\g(x)=\sqrt x$

And we want to find:

$(f\circ g)(1)$

This is the same as:

$f(g(1))$

So, to find the answer, find g(1) first:

$g(x)=\sqrt x\\g(1)=\sqrt1\\g(1)=1$

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$f(g(1))\\=f(1)$

And plug this into f(x):

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Therefore:

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Our answer is A

3 0

4 years ago

Read 2 more answers

Express 2100 as the product of its prime factors

aleksandrvk [35]

2100
/     \
2     1050/       \
2      525/       \
3      175/       \
5      35/       \
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7      1

8 0

4 years ago

PLEASE HELP!!! The question is below the graph.

IrinaVladis [17]

Answer:

Yes

Step-by-step explanation:

The line is good because it is representing the data accuratly because it is in the middle of all the data points and since all the point are near the line, it is accurate.

7 0

3 years ago

A store sells Brazilian coffee for $10 per lb. and Columbian coffee for $14 per lb. If the store decides to make a 150-lb. blend

Artemon [7]

Answer:

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

Step-by-step explanation:

Let "b" be the amount of Brazilian coffee, in pounds, required for the blend and "c" the amount of Colombian coffee required, in pounds.

Since there are two unknown variables a two-equation system is needed to solve the problem, we can set up one equation for weight and another for price as follows:

$b+c=150\\10*b+14*c=11*150$

Solve for "c" by multiplying the first equation by -10 and adding it to the second one:

$b+c=150\\10b+14c -10b-10c=11*150 -(10*150)\\4c=150\\c = 37.5$

Now, solve for b by replacing the value obtained into the first equation

$b+c=150\\b= 150 - 37.5\\b=112.5$

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

6 0

3 years ago