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Schach [20]
3 years ago
13

Alan writes 75 pages in 30 days In his journal, what is the average number of pages he writes each day? ( write as decimal show

your work)
Mathematics
2 answers:
Margaret [11]3 years ago
8 0

Answer:

Step-by-step explanation:

1.75/30=2.5

Each day he writing 2pages and half a page

Alla [95]3 years ago
5 0

Answer:

2.5 pages per day

Step-by-step explanation:

75÷30= 2.5

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What is 5 3/5% of 750?<br><br> Thanks in advance.
GREYUIT [131]
<h3>given:</h3>

5 \frac{3}{5} \% \: of \: 750

<h3>solution:</h3>

5 \frac{3}{5}  = 5.6

\frac{5.6\%}{100}  \times  \frac{x}{750}

= 42%

6 0
2 years ago
Pls help me pls pls ​
Ira Lisetskai [31]

7x = 2x + 20
5x = 20

X =4
3 0
3 years ago
Read 2 more answers
What are the ordered pairs of the
9966 [12]

Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

-3=x^2-5x+3

Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

x^2+x(m+n)+mn=0

which then must factor into

(x+m)(x+n)=0

And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
2 years ago
Write the equation that modeled the sequence 63,-21,7,-7/3,7/9
Ilya [14]

Answer:

an = 63(-1/3)^(n-1)

Step-by-step explanation:

This is a geometric sequence with first term 63 and common ratio -1/3.

The equation for the nth term  is

an = 63(-1/3)^(n-1).

6 0
3 years ago
Fifty people enter a contest in which three identical prizes will be awarded. in how many different ways can the prizes be award
Nina [5.8K]
<span>Provided that no one can receive more than one prize, there are 50*49*48= 117600 ways to distribute the prizes. The first prize can be given to any of the 50 people, the second to any of the remaining 49, and the third to the remaining of the 48, multiplying these possibilities together leads to the answer.</span>
4 0
3 years ago
Read 2 more answers
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