Moles of
,
![n_{H_2O}=\dfrac{42}{2\times 1 + 16}=\dfrac{42}{18}\\\\n_{H_2O}=2.33\ moles](https://tex.z-dn.net/?f=n_%7BH_2O%7D%3D%5Cdfrac%7B42%7D%7B2%5Ctimes%201%20%2B%2016%7D%3D%5Cdfrac%7B42%7D%7B18%7D%5C%5C%5C%5Cn_%7BH_2O%7D%3D2.33%5C%20moles)
Moles of acetic acid
,
![n_{A.A}=\dfrac{77}{1 + 12 + 3 + 12 + 16\times 2}=\dfrac{77}{60}\\\\n_{A.A}=1.28\ moles](https://tex.z-dn.net/?f=n_%7BA.A%7D%3D%5Cdfrac%7B77%7D%7B1%20%2B%2012%20%2B%203%20%2B%2012%20%2B%2016%5Ctimes%202%7D%3D%5Cdfrac%7B77%7D%7B60%7D%5C%5C%5C%5Cn_%7BA.A%7D%3D1.28%5C%20moles)
Mole fraction of water :
![M.F_{H_2O}=\dfrac{n_{H_2O}}{n_{H_2O}+n_{A.A}}\\\\M.F_{H_2O}=\dfrac{2.33}{2.33+1.28}\\\\M.F_{H_2O}=0.645](https://tex.z-dn.net/?f=M.F_%7BH_2O%7D%3D%5Cdfrac%7Bn_%7BH_2O%7D%7D%7Bn_%7BH_2O%7D%2Bn_%7BA.A%7D%7D%5C%5C%5C%5CM.F_%7BH_2O%7D%3D%5Cdfrac%7B2.33%7D%7B2.33%2B1.28%7D%5C%5C%5C%5CM.F_%7BH_2O%7D%3D0.645)
Therefore, mole fraction of water in this solution is 0.645 .
Hence, this is the required solution.
<span>HYDROSPHERE:
It is the liquid water component of the Earth. It contain seas, lakes, ponds, etc., It covers 70% of the Earth.
ATMOSPHERE:
It is another outer part of the earth. It contain nitrogen, oxygen, argon and other gases.
BIOSPHERE:
It is the region of the surface and atmosphere of the earth.</span>
Answer:
I am so sorry if I am wrong but my guess is no precipitate is formed.
Explanation:
Answer:
You have a chemical reaction that is occurring