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3 years ago

What type of reaction is

Chemistry

2 answers:

Alex17521 [72]3 years ago

8 0

Answer:

You have a chemical reaction that is occurring

Lisa [10]3 years ago

7 0

It is a single replacement reaction so C
Explanation:
An element and compound (Ca is the element and CuSO4 is the compound) switch to form a new element and compound (CaSO4 is the new compound and Cu is the new element)

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Predict the sign of enthalpy for reaction f+f=f2

guajiro [1.7K]

6+6=12

is your answer

6 0

3 years ago

A 0.105 L sample of an unknown HNO 3 solution required 35.7 mL of 0.250 M Ba ( OH ) 2 for complete neutralization. What is the c

oksano4ka [1.4K]

Answer: 0.17M

Explanation:

The equation for the reaction is :

2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O

From the balanced equation, we obtain :

nA = mole of acid = 2

nB = mole of the base = 1

From the question, we obtain:

Va = Vol. Of acid = 0.105L

Ma = conc. Of acid =?

Vb = Vol of base = 35.7 mL = 0.0357L

Mb = conc. of base = 0.25M.

We solve for the conc. of the acid using:

MaVa / Mb Vb = nA / nB

(Ma x 0.105) / (0.25x0.0357) = 2

Cross multiply to express in linear form. We have:

Ma x 0.105 = 0.25 x 0.0357 x 2

Divide both side by 0.105. We have

Ma = (0.25 x 0.0357 x 2) / 0.105

Ma = 0.17M

Therefore the concentration of the acid(HNO3) is 0.17M

3 0

3 years ago

What is the mass if 1.72 moles of sodium nitrate

alexgriva [62]

Answer:

146 g

Explanation:

Step 1. Calculate the <em>molar mass</em> of NaNO₃

Na = 22.99

N = 14.01

3O = 3 × 16.00 = 48.00

Total = 85.00 g/mol

Step 2. Calculate the <em>mass</em> of NaNO₃

Mass of NaNO₃ = 1.72 × 85.00/1

Mass of NaNO₃ = 146 g

8 0

3 years ago

Read 2 more answers

2C4H10+13o2= 8CO2+10H2O

Gennadij [26K]

Answer:

your answer will be between 16-17 moles

Explanation:

The combustion of butane is 2 C4H10 + 13 O2 = 8 CO2 + 10 H2O. Every two moles of C4H10 can produce 10 moles of water,

5 0

3 years ago

How much heat is required to vaporize 31.5 gg of acetone (C3H6O)(C3H6O) at 25 ∘C∘C? The heat of vaporization for acetone at this

KiRa [710]

Answer:

≅ 16.81 kJ

Explanation:

Given that;

mass of acetone = 31.5 g

molar mass of acetone = 58.08 g/mol

heat of vaporization for acetone = 31.0 kJ/molkJ/mol.

Number of moles = $\frac{mass}{molar mass}$

Number of moles of acetone = $\frac{31.5}{58.08}$

Number of moles of acetone = 0.5424 mole

The heat required to vaporize 31.5 g of acetone can be determined by multiplying the number of moles of acetone with the heat of vaporization of acetone;

Hence;

The heat required to vaporize 31.5 g of acetone = 0.5424 mole × 31.0 kJ/mol

The heat required to vaporize 31.5 g of acetone = 16.8144 kJ

≅ 16.81 kJ

4 0

3 years ago