Let's Evaluate Complete the table below by giving the solute and the solvent of the given types and examples of solution.

Which statement refers to the quantum mechanical model? A) Electrons move in a circular path about the nucleus. B) Electrons can

Yuri [45]

Answer:

Electrons are in "orbitals", regions of space where there is high probability of being found.

Explanation:

The Wave mechanical model of the atom does not restrict the electrons to certain energy levels only as in the Bohr's model, instead it describes a region around the nucleus called an orbital, where there is a high probability of finding an electron with a certain amount of energy.

Each energy level is composed of one or more orbitals and the distribution of electrons around the nucleus is determined by the number and kind of energy levels that are occupied.

3 0

3 years ago

Titration is a type of experiment that can be performed to investigate a neutralization reaction. The equivalence point is when

Rom4ik [11]

Answer:

74.0 mL

Explanation:

In the equivalence point we have:

$n_{a} = n_{b}$

Where:

$n_{a}$ is the number of moles of the acid

$n_{b}$ is the number of moles of the base

$M_{a}V_{a} = M_{b}V_{b}$

Where M is the concentration and V is the volume

Hence the volume of the base is:

$V_{b} = \frac{M_{a}V_{a}}{M_{b}} = \frac{1.50 M*43.6 mL}{0.884 M} = 74.0 mL$

Therefore, is needed 74.0 mL of the potassium hydroxide solution to reach the equivalence point.

I hope it helps you!

4 0

3 years ago

You're leaving a carnival and you're pumped because a clown just handed you a red, helium- filled balloon. But then, something t

bixtya [17]

Because the helium inside it is lighter than air , hence it rises up
The balloon from our breath contains carbon dioxide which is heavier than air so it doesn’t rise

6 0

3 years ago

1)state Non-Mendillian's Law of Inheritance.

ioda

Answer:

These questions are not chemistry darling. You have chosen the wrong subject

8 0

3 years ago

Compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl2(aq) at standard pressure

Galina-37 [17]

Answer : The correct option is, (1) lower

Explanation :

Formula used for lowering in freezing point :

$\Delta T_f=i\times k_f\times m$

where,

$\DeltaT_b$ = change in freezing point

$k_b$ = freezing point constant

m = molality

i = Van't Hoff factor

According to the question, we conclude that the molality of the given solutions are the same. So, the freezing point depends only on the Van't Hoff factor.

Now we have to calculate the Van't Hoff factor for the given solutions.

(a) The dissociation of $KCl$ will be,

$KCl\rightarrow K^++Cl^-$

So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2

(b) The dissociation of $CaCl_2$ will be,

$CaCl_2\rightarrow Ca^{2+}+2Cl^-$

So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3

The freezing point depends only on the Van't Hoff factor. That means higher the Van't Hoff factor, lower will be the freezing point and vice-versa.

Thus, compared to the freezing point of 1.0 M $KCl(aq)$ at standard pressure, the freezing point of 1.0 M $CaCl_2(aq)$ at standard pressure is lower.

4 0

3 years ago