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liq [111]
2 years ago
13

How many moles of propane react when 294 g of CO2 form? C3H8 +502 → 3CO₂ + 4H₂O

Chemistry
1 answer:
tatiyna2 years ago
7 0

2.23 moles of propane react when 294 g of CO₂ is formed .

<h3>What is moles ?</h3>

Moles is a unit which is equal to the molar mass of an element.

A reaction is given

C₃H₈ +50₂ → 3CO₂ + 4H₂O

Grams of CO₂ formed = 294 gm

In moles = 294 /44 = 6.68 moles.

Let x be the moles of C₃H₈ is x

Mole ratio of CO₂ to C₃H₈ = 3 : 1

so

6.68 /x = 3/1

x = 6.68 /3 = 2.23 moles

Therefore 2.23 moles of propane react when 294 g of CO₂ is formed .

To know more about Moles

brainly.com/question/26416088

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Hello please help me on this problem thanks.sc​
Sedbober [7]
The second answer, 80 J
3 0
3 years ago
(45 pts) In which reaction is carbon reduced?
Sidana [21]

Answer:

Reductio is gain of electrons, while oxdation is loss. The oxidtion states of carbon in the reaction will show either of oxidation or reduction occurrence.

C_{2} H_{2}(g)  +H_{2} (g) → C_{2} H_{4}(g)

Explanation:

Electrons displacement is explained for each reaction below:

  1. +2 to +4 = loss of 2 more lectrons-------oxidation
  2. +4 throughout reaction----no exchange of electrons
  3. -4 to +4 =  loss of 4 electrons-----oxidation
  4. 0 to -2 = gain of 2 electrons-----reduction
5 0
3 years ago
What are the answer??
MrMuchimi

Answer:?

Explanation:None

4 0
3 years ago
What is the molarity if a solution that contains 289 grams of sugar in a 2 liter solution?? Molar mass of source is 342.2965g/mo
Olegator [25]

<u>Answer;</u>

= 0.422 M

<h3><u>Explanation;</u></h3>

Molarity or concentration is the number of moles of a solute in 1 liter of a solution.

Therefore; Molarity = n/V ; where n is the number of moles and V is the volume of the solution in L.

Number of moles = Mass/molar mass

                             = 289 g/342.2965g/mol

                             = 0.844 Moles

Therefore;

Molarity = 0.844 moles/ 2L

              = 0.422 M

8 0
4 years ago
You are assigned the task of separating a desired granular material, with a density of 3.26 g/cm3, from an undesired granular ma
Svetradugi [14.3K]

Answer:

diiodomethane

Explanation:

The densities of each of the liquids mentioned in the question are stated below;

CCl4- 1.59 g/cm^3

Hexane- 0.672 g/cm^3

Benzene- 0.8765 g/cm^3

Diiodomethane- 3.3 g/cm^3

Clearly, the density of diiodomethane methane is almost the same as that of the desired granular material, hence the undesired granular material having a density of 2.04 g/cm3 will float in diiodomethane thus separating the two granular materials.

5 0
3 years ago
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