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2 years ago

The combination of units written kg·m/s2 can be used for which of the following?

2 answers:

7 0

C. force because the force able to communicate to a mass of one kilogram an accerelation of 1m/s²
Kg.m
F= -------------
S²

shusha [124]2 years ago

5 0

Force = (mass) (acceleration) = (kg) (m/s^2)

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What is the net force acting on a 3000g sled that accelerated at 5 m/s2 ?

user100 [1]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

3000 g = 3 kg

We have

net force = 3 × 5 = 15

We have the final answer as

Hope this helps you

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2 years ago

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2 years ago

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Serga [27]

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Explanation:

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2 years ago

Write an algebraic expression to repro<br> 1.4 times a number, increased by 7

liberstina [14]

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2 years ago

How many moles are present in

olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of $N_{2}$ molecule.

(b) There are 2 moles present in $12.044 \times 10^{23}$ particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of $N_{2}$ is 28 g/mol so its number of moles are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol$

So, there are 0.428 moles present in 12 g of $N_{2}$ molecule.

(b). According to the mole concept, 1 mole of every substance contains $6.022 \times 10^{23}$ atoms.

Therefore, moles present in $12.044 \times 10^{23}$ particles are calculated as follows.

$Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol$

So, there are 2 moles present in $12.044 \times 10^{23}$ particles of oxygen.

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2 years ago