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serg [7]
3 years ago
12

Which of the following is a example of an inherited behavior

Chemistry
1 answer:
AURORKA [14]3 years ago
4 0

Answer: A. A spider Spinning a Web.

Explanation: That one should be it because every spider inherits that. It's in their blood. They don't need to be taught. A dog balancing a ball on its nose isn't right because you have to train them to do that. Same with the mouse going through a maze. A cheeta hunting prey isn't inherited. Their mother has to teach them or at least show them when they get older.

A is definitely the answer. It's an inheritance.

Hope this helps you out! ☺

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A 5.00-L tank contains helium gas at 1.50 atm. What is the pressure of the gas in mmHg
bulgar [2K]

Answer:

  1140 mmHg

Explanation:

1 atmosphere is 760 mmHg, so 1.5 atmospheres is ...

  1.5×760 mmHg = 1140 mmHg

4 0
3 years ago
onsider the following reaction: CaCN2 + 3 H2O → CaCO3 + 2 NH3 105.0 g CaCN2 and 78.0 g H2O are reacted. Assuming 100% efficiency
mestny [16]

Answer : The excess reactant is, H_2O

The leftover amount of excess reagent is, 7.2 grams.

Solution : Given,

Mass of CaCN_2 = 105.0 g

Mass of H_2O = 78.0 g

Molar mass of CaCN_2 = 80.11 g/mole

Molar mass of H_2O = 18 g/mole

Molar mass of CaCO_3 = 100.09 g/mole

First we have to calculate the moles of CaCN_2 and H_2O.

\text{ Moles of }CaCN_2=\frac{\text{ Mass of }CaCN_2}{\text{ Molar mass of }CaCN_2}=\frac{105.0g}{80.11g/mole}=1.31moles

\text{ Moles of }H_2O=\frac{\text{ Mass of }H_2O}{\text{ Molar mass of }H_2O}=\frac{78.0g}{18g/mole}=4.33moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3

From the balanced reaction we conclude that

As, 1 mole of CaCN_2 react with 3 mole of H_2O

So, 1.31 moles of CaCN_2 react with 1.31\times 3=3.93 moles of H_2O

From this we conclude that, H_2O is an excess reagent because the given moles are greater than the required moles and CaCN_2 is a limiting reagent and it limits the formation of product.

Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles

Now we have to calculate the mass of excess reactant.

\text{ Mass of excess reactant}=\text{ Moles of excess reactant}\times \text{ Molar mass of excess reactant}(H_2O)

\text{ Mass of excess reactant}=(0.4moles)\times (18g/mole)=7.2g

Thus, the leftover amount of excess reagent is, 7.2 grams.

8 0
3 years ago
One mole of water weights?
Gemiola [76]

Answer:

c 18.0ml

Explanation:

The average mass of one H2O molecule is 18.02 amu. The number of atoms is an exact number, the number of mole is an exact number; they do not affect the number of significant figures. The average mass of one mole of H2O is 18.02 grams. This is stated: the molar mass of water is 18.02 g/mol.

8 0
3 years ago
Which of the following is the highest level of organization (least specific)? a. genus c. family b. class d. order
yKpoI14uk [10]
Hello

Your answer would be:

a. genus
4 0
3 years ago
Asolution has a pH of 8. Which best describes the solution?
alekssr [168]

Answer:

a weak base

Explanation:

pH levels:

0-3 Strong Acid

4-6 Weak Acid

7 Neutral

8-10 Weak Base

11-14 Strong Base

6 0
3 years ago
Read 2 more answers
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