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dezoksy [38]
3 years ago
14

In the hypothetical reaction below, substance A is consumed at a rate of 2.0 mol/L·s. If this reaction is at dynamic equilibrium

, at what rate will substance B be consumed?

Chemistry
2 answers:
vazorg [7]3 years ago
6 0
Dynamic equilibrium means that the proportion is equal. The fact that the equation is at equilibrium suggests that the equation is balanced and therefore the answer must be 2.0 mol because that allows the products and reactants to level out...
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

2.0 mol on Ed

Explanation:

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What is a polyprotic buffer?
coldgirl [10]
Buffers - mixtures of conjugate acid and conjugate base at ±1 pH unit from pH = pKa. Resistant to changes in pH in response to small additions of H+ or OH-. ... Polyprotic acids - dissociation of each H+ can be treated separately if the pKa values are different
3 0
2 years ago
Determine the volume of a substance that has a density of 1.84 g/ml and a mass of 12 grams
vazorg [7]
Hey there!:

density = mass / volume

1.84 g/mL =  12 g / V

V =  12 / 1.84

V = 6.521 mL

hope this helps!
             
5 0
2 years ago
PH of 0,035M HCl? How to count if your calculator hasn't got -lg?
IrinaK [193]

<u>Given information:</u>

Concentration of HCl = 0.035 M

<u>To determine:</u>

pH of the solution

<u>Explanation:</u>

Hydrochloric acid, HCl is a strong acid. It will completely dissociate to give H+ and Cl- ions

HCl → H+ + Cl-

Hence the concentration of H+ = Cl- = 0.035M

Now, pH measures the strength of H+ ions in a given solution. It is expressed as:

pH = -log[H+]

pH (HCl) = -log(0.035) = 1.46

Ans: pH of 0.035M HCl is 1.46

6 0
2 years ago
A 0.300 m solution of hcl is prepared by adding some 1.50 m hcl to a 500 ml volumetric flask and diluting to the mark with deion
liberstina [14]
In dilution we add distilled water to decrease the concentration of required sample from high concentration to lower concentration
The law used for dilution:
M₁V₁]Before dilution = M₂V₂] After dilution
M₁ = 1.5 M
V₁ = ?
M₂ = 0.3 M
V₂ = 500 ml
1.5 * V₁ = 0.3 * 500 ml
so V₁ = 100 ml and it completed to 500 ml using 400 ml deionized water
8 0
3 years ago
A solution of the weak acid HA is prepared by dissolving 2.70 g of HA in 100.0 mL water. The solution is titrated, and the equiv
ELEN [110]

Answer:

i.2iu

Explanation:

3 0
2 years ago
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