Answer:
How many grams of copper (II) nitrate is formed
Answer:
76.25cm
Explanation:
38cm + 56cm +97cm +114cm = 305cm
305cm÷4 = 76.25cm
Answer:
<h2>59.1 m</h2>
Explanation:
The height of the object can be found by using the formula

where
p is the potential energy
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have

We have the final answer as
<h3>59.1 m</h3>
Hope this helps you
Answer:
Question not very specific, but here is an answer you might be looking for. Density of object at 2 degrees C, 0.99997 g/mL. Hope it IS the answer you are looking for!
Explanation:
Answer:
Therefore, the rate of change in the amount of salt is 

Explanation:
Given:
Initial volume of water
lit
Flowing rate = 5 
The rate of change in the amount of salt is given by,
( Rate of salt enters tank - rate of sat leaves tank )
Since tank is initially filled with water so we write that,

Let amount of salt in the solution is
,


Therefore, the rate of change in the amount of salt is 
