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4 years ago

6

Translate the following sentence into an algebraic inequality: The quotient of a number, x, and nine is less than eight more tha

n the product of five and the same number x.

1 answer:

dusya [7]4 years ago

8 0

Answer:

x/9-8x+5x

Step-by-step explanation:

I can't help but to solve it:

x/9=9x

9x-8x+5x=6x

= 6x

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16 times what equals 40

GarryVolchara [31]

It cannot equal 40 but it can be multiplied by 2 and become 42

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For brett's birthday his mother gave out colorful birthday hats that were cone shaped. the opening of the bottom of the hat was

nika2105 [10]

The volume of cone is calculated by the formula $V= \frac{1}{3} \pi R^2H$ , where H is a height of cone and R is a radius of the bottom.
In your case, R=3 cm and R=7 cm. Then $V= \frac{1}{3} \pi* 3^2*7= \frac{63\pi}{3} =21\pi$ .
Answer: The volume of candy is 21π.

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3 years ago

Let f (x)=x^2 – 8x + 19.

Darina [25.2K]

Answer:

its basically (4,-3)

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3 years ago

A. f(x) = 2|2| is differentiable overf<br> X<br> B. g(x) = 2 + || is differentiable over<br> -f

kramer

Recall the definition of absolute value:

• If <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>

• If<em> x</em> < 0, then |<em>x</em>| = -<em>x</em>

<em />

(a) Splitting up <em>f(x)</em> = <em>x</em> |<em>x</em>| into similar cases, you have

• <em>f(x)</em> = <em>x</em> ² if <em>x</em> ≥ 0

• <em>f(x)</em> = -<em>x</em> ² if <em>x</em> < 0

Differentiating <em>f</em>, you get

• <em>f '(x)</em> = 2<em>x</em> if <em>x</em> > 0 (note the strict inequality now)

• <em>f '(x)</em> = -2<em>x</em> if <em>x</em> < 0

To get the derivative at <em>x</em> = 0, notice that <em>f '(x)</em> approaches 0 from either side, so <em>f</em> <em>'(x)</em> = 0 if <em>x</em> = 0.

The derivative exists on its entire domain, so <em>f(x)</em> is differentiable everywhere, i.e. over the interval (-∞, ∞).

(b) Similarly splitting up <em>g(x)</em> = <em>x</em> + |<em>x</em>| gives

• <em>g(x)</em> = 2<em>x</em> if <em>x</em> ≥ 0

• <em>g(x)</em> = 0 if <em>x</em> < 0

Differentiating gives

• <em>g'(x)</em> = 2 if <em>x</em> > 0

• <em>g'(x)</em> = 0 if <em>x</em> < 0

but this time the limits of <em>g'(x)</em> as <em>x</em> approaches 0 from either side do not match (the limit from the left is 0 while the limit from the right is 2), so <em>g(x)</em> is differentiable everywhere <u>except</u> <em>x</em> = 0, i.e. over the interval (-∞, 0) ∪ (0, ∞).

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3 years ago

In Exercises 8-10, sketch the figure described.

Lunna [17]

The sketch answers to question 8, 9 and 10 is given in the image attached.

<h3>What is an intersecting lines?</h3>

A link is known to be intersecting if two or more lines are said to have cross one another in a given plane.

Note that the intersecting lines are known to be one that often share a common point, and it is one that can be seen on all the intersecting lines, and it is known to be the point of intersection.

Looking at the image attached, you can see how plane A and line c intersecting at all points on line c and also GM and GH and line CD and plane X as they are not intersecting

Therefore, The sketch answers to question 8, 9 and 10 is given in the image attached.

Learn more about intersecting lines from

brainly.com/question/2065148

#SPJ1

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2 years ago