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nikdorinn [45]
3 years ago
14

If a = i - j , b = i+j+k and c be a vector such that a x c + b = o and a.c= 4, then IcI2 is equal to​

Mathematics
2 answers:
scZoUnD [109]3 years ago
6 0
It is correct because it is
docker41 [41]3 years ago
4 0

Answer: IcI^2 = 9.5

Step-by-step explanation:

The data is:

a = (1, -1, 0)

b = (1, 1, 1)

axc = -b

then if c = (A, B, C) we have that:

axc = (-C, -C, A + B)

then we have the equality

-C = 1

A + B = 1

we also have that:

a.c = 1*A + (-1)*B + 0 *C = 4

A - B = 4

then we have two equations for A and B

A + B = 1

A - B = 4

we isolate A in the second equation and get:

A = 1 - B

now we replace it in the second equation

(1 - B) - B = 4

1 - 2B = 4

B =(4 -1)/(-2) = -3/2

then:

A + (-3/2) = 1

A = 1 + 3/2 = 2/2 + 3/2 = 5/2

we have that c = (5/2, -3/2, -1)

then IcI^2 = (5/2)^2 + (-3/2)^2 + (-1)^2 = 9.5

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A patrolman spends three times as many hours patrolling as she does completing paper work. If she works 36 hours per week, how m
fomenos

Answer:

27 hours

Step-by-step explanation:

Let her work "x" hours for paperwork

Since, patrolling amount of hours is THREE TIMES that,

Patrolling = 3x hours

Total Hours = 36

That is including paperhour work (x) and patrolling (3x). So we can setup an equation in x and solve for x first:

x + 3x = 36

4x = 36

x = 36/4

x = 9 hours

Amount of Hours for Patarolling = 3x hours = 3(9) = 27 hours

So, she spends 27 hours patrolling

4 0
3 years ago
How do you solve 34.86 x 1.2?
Nezavi [6.7K]

Answer: 41.832

Step-by-step explanation:

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3486 x 12 which equals 41832 then You would move the decimal up from 3 spaces from the 2 from 41832 which would put the decimal between the 1 and 8

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3 years ago
3x – 2y+3<br> 3y - 2x<br><br> X=7 Y=6
faust18 [17]
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8 0
3 years ago
Given that these simultaneous equations
Tatiana [17]

The value of k is(3\sqrt{ 10})/2

<h3>How to solve the simultaneous equation?</h3>

Given:

x-y=k.............(eq i)

2x²+y²-15..............(eq ii)

We would make y the subject formula in eq ii

2x²+y²-15= 0

2x² + y²= 15

y²= 15-2x²

y= \sqrt{15-2x^2}...........(eq iii)

Substitute the value of y into eq i

x-(\sqrt{15-2x^2}= k

x- (\sqrt{15} - 2x= k

k= (3\sqrt{ 10})/2

Read more about simultaneous equations here:

brainly.com/question/16863577

#SPJ1

3 0
2 years ago
Help me with this please !!
avanturin [10]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the line y = - x

a point (x, y ) → (- y, - x ), thus

T(- 1, 3 ) → T'(- 3, 1 )

U(- 1, 10 ) → U'(- 10, 1 )

V(- 2, 4 ) → V'(- 4, 2 )

6 0
3 years ago
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