Answer:
7 L of H₂.
Explanation:
The balanced equation for the reaction is given below:
2H₂ + O₂ —> 2H₂O
From the balanced equation above,
1 L of O₂ required 2 L of H₂.
Finally, we shall determine the volume of H₂ required to react with 3.5 L of O₂. This can be obtained as follow:
From the balanced equation above,
1 L of O₂ required 2 L of H₂.
Therefore, 3.5 L of O₂ will require
= 3.5 × 2 = 7 L of H₂.
Thus, 7 L of H₂ is required to for the reaction.
Hey there!:
The fractional saturation y is defined as :
y = [ L ] / Kd + [ L ]
where :
[ L ] = concentration of binding ligand
Kd = 400 nm
Answer: The final temperature of both substances at thermal equilibrium is 301.0 K
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of gold = 31.5 g
= mass of water = 63.4 g
= final temperature = ?
= temperature of gold = 
= temperature of water = 
= specific heat of gold = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![-31.5\times 0.129\times (T_{final}-342.4)=[63.4\times 4.184\times (T_{final}-300.4)]](https://tex.z-dn.net/?f=-31.5%5Ctimes%200.129%5Ctimes%20%28T_%7Bfinal%7D-342.4%29%3D%5B63.4%5Ctimes%204.184%5Ctimes%20%28T_%7Bfinal%7D-300.4%29%5D)
The final temperature of both substances at thermal equilibrium is 301.0 K
<span>While
treating food with gamma rays kills microorganism by damaging their DNA, the energy
of gamma rays rips off electrons from atoms hence ionizing them (causing free radicals).
However, gamma rays do not make the food atoms radioactive. The body has a natural
mechanism of riding the body of free radicals. However, large quantities of radicals in the body can cause
damage.</span>
<h3>
Answer:</h3>
pH = 8.66
<h3>
Explanation:</h3>
- The pH refers to the acidity or alkalinity of a solution.
- It is calculated by getting the negative logarithm of Hydrogen ions concentration.
In this case;
we are given [OH⁻] as 4.6 x 10^-6 M
We are required to calculate the pH
We need to know that;
pH + pOH = 14
pOH = -log[OH⁻]
To get the pH we can calculate the pOH first,
pOH = -log[4.6 x 10^-6 M]
= 5.34
but, pH + pOH = 14
Therefore, pH = 14 - pOH
= 14 - 5.34
= 8.66
Therefore, the pH of the solution is 8.66
