Answer:
90.
Explanation: yea and I will be back at your
Answer:
Suppose you added some solid NaCl to a saturated solution of NaCl at 20℃ and warmed the mixture to 40℃. What would happen to the added NaCl?
Explanation:
can you help with this one
B. 3.0 mol·L⁻¹ NaCl
Explanation:
Freezing point is a colligative property: it depends only on the number of particles in solution.
The for freezing point depression ΔT_f is
ΔT_f = iK_fb
where
i = the number of moles of particles available from one mole of solute
K_f = the molal freezing point depression constant
b = the molal concentration of the solute
All your solutions are aqueous NaCl. They differ only in their concentrations.
Thus, the most concentrated solution will have the greatest freezing point depression and the lowest freezing point.
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The correct answer is 3.4 moles of sulfuric acid (H₂SO₄) are needed to react completely with 6.8 moles of lithium hydroxide.
2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O
The given chemical equation is balanced.
By using stoichiometry, one can witness the following:
2 moles of LiOH requires 1 mole of H₂SO₄
So, 6.8 moles of LiOH requires (1/2) × 6.8 = 3.4 moles of H₂SO₄
