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dmitriy555 [2]
3 years ago
8

The photograph shows the most abundant substance on Earth's su Which fact about this substance tells you that it is a compound?

A. It is a colorless liquid that is inflammable. B. It is made up of atoms that have mass and take up space c. It can be separated into two substances by a chemical pro D. It appears to be the same type of matter throughout.​
Chemistry
2 answers:
Arlecino [84]3 years ago
5 0

Answer:

B. It is made up of atoms that have mass and take up space

rosijanka [135]3 years ago
4 0

Answer:

the answer to this question is b

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3 years ago
Determine the [OH−]
Katarina [22]

Answer:

Explanation:

[H+] = 4.7 x 10⁻⁵ M

[H+][OH⁻] = 10⁻¹⁴

[OH⁻] = \frac{10^{-14}}{4.7\times 10^{-5}}

= .2127 x 10⁻⁹ M

pH = - log[H+]

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= - log4.7 + 5

= 4.328

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pOH = 14 - pH

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3 years ago
The point along a planet's orbit where it is closest to the sun is called the ____
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Perihelion is when a planet is closest to the sun and aphelion is when it is farthest from the sun. Perihelion is the correct answer.

6 0
3 years ago
Select two statements that describe how elements in the same group are similar to each other.
kolbaska11 [484]

Answer:

A: Elements in the same group share the same number of valence electrons.

D: Elements in the same group share the same reactive properties.

Explanation:

A periodic group is simply the arrangement of elements vertically on the periodic table.

There are about 8 main groups of elements on the periodic table.

  • Elements in the same group have the same number of valence electrons. This is usually observed  in their group numbers.
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3 years ago
What is the mass % of acetone in a 1.77 M solution of acetone (MM = 58.08 g/mol) in water? The density of the solution is 0.971
bija089 [108]

Answer:

\%m/m=10.6\%

Explanation:

Hello!

In this case, since the by-mass percent is defined by:

\%m/m=\frac{m_{solute}}{m_{solution}} *100\%

Thus, since the given 1.77 M solution is given in terms of mol/L, we need to compute the mass of acetone via its molar mass and the volume of solution in L to g via the density:

\%m/m=1.77\frac{mol}{L}*\frac{58.08g}{1mol}*\frac{1L}{1000mL}*\frac{1mL}{0.971g}   *100\%\\\\\%m/m=10.6\%

Best regards!

6 0
3 years ago
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