The answer would be: b. The spring constant is 20 N/m
Answer:
d = (75 i ^ + 93 j ^ + 27 k ^) m
, d2 = (900 i ^ + 1116 j ^ + 324 k ^) m
Explanation:
The two objects are in circular orbit together, therefore with the same angular velocity, after the launch they move with the relative velocity, so we can use the kinematic relation
v = d / t
d = v t
Reduce time to units SI
t = 5 min (60 s / 1 min) = 300 s
X axis
x = vₓ t
x = 0.25 300
x = 75 m
Y axis
y =
t
y = 0.31 300
y = 93 m
Z axis
z=
t
z = 0.09 300
z = 27 m
d = (75 i ^ + 93 j ^ + 27 k ^) m
For the time of 1 h
t2 = 1 h (3600s / 1 h) = 3600
x2 = 900 m
y2 = 1116 m
z2 = 324 m
d2 = (900 i ^ + 1116 j ^ + 324 k ^) m
Electrical kettle:
P = 2 KW = 2000 W
U = 200 V
⇒ I = P/U = 2000 / 200 = 10 A
We apply the Law of Ohm:
R = U / I = 200V / 10A = <u>20 Ω</u>
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Electrical heater:
P = 1 KW = 1000 W
U = 240 V
⇒ I = P/U = 1000 / 240 = 4,16 A
We apply the Law of Ohm:
R = U / I = 240V / 4,16A = <u>57,69 Ω</u>
<u>Answer:</u>
The device with the highest resistance is <u>the electric heater.</u>
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Answer:
The minimum difference between the lengths of the two tubes should be 0.385 meters.
Explanation:
As we known that for any two waves to arrive in phase at any point the difference in the path traveled by the waves should be an integral multiple of the wavelength of the wave.
Mathematically we can write:

For the given wave we have

Applying values we get

Thus the minimum difference in the lengths of the tubes can be obtained by putting the value of n = 1
