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3 years ago

A car starts from rest and gains a velocity of 20 m/s in 10 s.Calculate acceleration

Physics

2 answers:

tiny-mole [99]3 years ago

6 0

Explanation:

<h3>Acceleration = 20-0/10= 2m/s²</h3><h2>I NEED BRAINLIEST ✌️ PLZ</h2>

fgiga [73]3 years ago

6 0

Explanation:

Acceleration = 20-0/10 = 2 m/s ²

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A physics student mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them

Tatiana [17]

Answer:

A) q₂ = 75.98 cm, B) q₂' = 115.38 cm, C)

Explanation:

A) This is an exercise in geometric optics, as the two lenses are separated by a greater distance than their focal lengths from each lens, they must be worked as independent lenses.

Lens 1. More to the left

let's use the constructor equation

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where f is the focal length, p and q are the distance to the object and the image, respectively,

We must assume a distance to the object to perform the calculation, suppose that the object is 50 cm from lens 1 that is further to the left of the system.

$\frac{1}{q_1} = \frac{1}{f} - \frac{1}{p}$

$\frac{1}{q_1} = \frac{1}{14.8} - \frac{1}{50}$

1 / q₁ = 0.04756

q₁ = 21.0227 cm

this image is the object for the second lens that has f₂ = 14.8 cm

the distance must be measured from the second lens

p₂ = 39.4 -q₁

p₂ = 39.4 -21.0227

p₂ = 18.38 cm

let's use the constructor equation

1 / q₂ = 1 / f - 1 / p2

$\frac{1}{q_2} = \frac{1}{14.8} - \frac{1}{18.38}$

$\frac{1}{q_2}$ = 0.01316

q₂ = 75.98 cm

measured from the second lens

B) the position of the final image with respect to the first lens is

q₂’= q₂ + 39.4

q₂'= 75.98 +39.4

q₂' = 115.38 cm

C) the magnification of a lens is

m = - q / p

in this case the image measured from lens 2 is q2 = 75.98 cm

the distance to the object from the first lens is p1 = 50cm

m = - 75.98 / 50

m = -1.5 X

the negative sign indicates that the image is inverted

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3 years ago

Earlier we discussed the concept of isostasy, where lower density rocks rise higher than higher density rocks. How is the variat

Elena L [17]

The variation of water depth at spreading centers (ridges) controlled by isostasy as convective cooling cools the rocks much more effectively the than heat conduction.

<h3>What is convective heat transfer?</h3>

When heat transfer takes place between the two fluids in direct or indirect contact.

The lithosphere cools when it moves away from the ridge axis by sea floor spreading. The cooler rocks have low density, so the sea floor gets deeper as the lithosphere gets more dense.

Thus, the convective cooling cools the rocks much more effectively the than heat conduction.

Learn more about convective heat transfer

brainly.com/question/10219972

#SPJ1

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2 years ago

Sound wave W has amplitude ‘A' and frequency ‘f'. Sound wave X is louder and lower in pitch than sound wave W. What can be said

ra1l [238]

Answer:

Sound wave X amplitude is greater than 'A' and its frequency is lesser than

'f'

Explanation:

The pitch of a sound is dictated by the frequency of the sound wave, while the loudness is dictated by the amplitude.

A high pitch sound corresponds to a high frequency and a low pitch sound corresponds to a low frequency.

The larger the amplitude of the waves, the louder the sound and vice-versa.

From the question,

Sound wave W has amplitude ‘A' and frequency 'f' and

Sound wave X is louder and lower in pitch than sound wave W.

Since sound wave X is louder, this means its amplitude is greater than 'A'.

Also, since sound wave X is lower in pitch, this means its frequency is lesser than 'f'.

7 0

3 years ago

What happen to internal energy of water at 0 degree?

miss Akunina [59]

Answer:

internal energy apparently increases.

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3 years ago

A metal wire of resistance R is cut into five equal pieces that are then placed together side by side to form a new cable with a

Alina [70]

Answer:

R / 25

Explanation:

Let the initial length of the wire is L and its resistance is R.

Now the length is cut into 5 equal parts.

The resistance of a wire is directly proportional to the length of the wire, thus, the resistance of each portion of the wire is R/5.

Now the five pieces are connected in parallel combination, the equivalent resistance is

$\frac{1}{R_{eq}}=\frac{5}{R}+\frac{5}{R}+\frac{5}{R}+\frac{5}{R}+\frac{5}{R}$

$R_{eq}=\frac{R}{25}$

Thus, the resistance of the new cable is R / 25.

8 0

3 years ago

A car starts from rest and gains a velocity of 20 m/s in 10 s.Calculate acceleration​

A car starts from rest and gains a velocity of 20 m/s in 10 s.Calculate acceleration