A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2).
rule (x + 7, y − 1)
To find new coordinates we add 7 with x and subtract 1 from y
A(−2, 2) -----> A' (5,1)
B(−2, 4) -------> B' (5, 3)
C(2, 4) ---------> C' (9, 3)
D(2, 2) -------->D' (9, 1)
Characteristics
When we connect all the points by line segments, the line A'B' will be parallel to C'D'.
Also, B'C' parallel to A'D'.
All the four lines forms a rectangle .
The area of the given square pyramid is:
total area = 1,100 inches squared.
<h3 /><h3>
How to get the area of the pyramid?</h3>
On the second image, we can see that the pyramid is conformed of a square base and 3 triangles.
To get the surface area of the pyramid, we can just get the area of each of these simpler parts.
The base is a square of 22 in by 22 in, then the area of the base is:
B = (22in)*(22 in) = 484 in^2
For each triangle, the area will be:
A = (base side)*(height)/2
A = (22in)*(14in)/2 = 154 in^2
And we have 4 of these triangles, then the total area of the pyramid will be:
total area = B + 4*A = 484in^2 + 4*(154 in^2) = 1,100 in^2
If you want to learn more about square pyramids:
brainly.com/question/22744289
#SPJ1
Use the formula 0 = b^2-4ac
0 = -b^2-4(2)(-9)
0 = -b^2+72
b^2 = 72
b = square root of 72
b = 2 real numbers
X-intercept = -3
y- intercept = -6
