Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
Answer:
-2 5/9
Step-by-step explanation:
w + (-x) - 2/3
Let w = -5/9 and x = 4/3
-5/9 - 4/3 - 2/3
Get a common denominator
-5/9 -4/3*3/3 -2/3*3/3
-5/9 -12/9 -6/9
Add
-23/9
Change to a mixed number
-2 5/9
Answer:
Step-by-step explanation:
Slant asymptote is y = -
x -
Answer:
51
Step-by-step explanation:
10 by 5 is 50 plus 9 is 59 subtract 8 is 51
10*5+9-8 = 51